### Stoichiometry and Chemical Reactions**Problem Statement:****2.** You start with 2.46 g of KClO3 and heat it. Use stoichiometry to calculate the mass (g) of KCl produced by the reaction.---**Step-by-Step Solution:**1. **Write the balanced chemical equation for the decomposition of KClO3:** \[2KClO_3 \rightarrow 2KCl + 3O_2\]2. **Calculate the molar mass of KClO3 and KCl:** - KClO3: \( 39.10 (\text{K}) + 35.45 (\text{Cl}) + 3 \times 16.00 (\text{O}) = 122.55 \, \text{g/mol} \) - KCl: \( 39.10 (\text{K}) + 35.45 (\text{Cl}) = 74.55 \, \text{g/mol} \)3. **Convert grams of KClO3 to moles:** Moles of KClO3: \[ \frac{2.46 \, \text{g KClO}_3}{122.55 \, \text{g/mol}} = 0.0201 \, \text{mol KClO}_3 \]4. **Use the stoichiometric ratios from the balanced equation to find moles of KCl produced:** According to the balanced equation, \(2 \, \text{mol KClO}_3\) produces \(2 \, \text{mol KCl}\): \[ 0.0201 \, \text{mol KClO}_3 \times \frac{2 \, \text{mol KCl}}{2 \, \text{mol KClO}_3} = 0.0201 \, \text{mol KCl} \]5. **Convert moles of KCl to grams:** \[ 0.0201 \, \text{mol KCl} \times 74.55 \, \text{g

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Answered: 2. You start with 2.46 g of KCIO345)…

2. You start with 2.46 g of KCIO345) and heat it. Use stoichiometry to calculate the mass (g) of KCI produced by the reaction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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