2. You are hanging out with your friend Angel, and you decided to warm up some snacks in the microwave. Angle then tells you that he doesn't microwave his food because he read in an article that microwave radiation is even more dangerous than being exposed to UV light because of the high levels of energy in microwave radiation. You disagree with you friend and determine the energy of both types of electromagnetic radiation to prove him wrong. Assume that microwaves have a frequency of 520 MHz and that UV light has a frequency of approximately 780 THz. A. Could you tell if Angel is wrong without any mathematical process, given only the frequencies above? Explain B. Calculate the energy of photons of each type.
2. You are hanging out with your friend Angel, and you decided to warm up some snacks in the microwave. Angle then tells you that he doesn't microwave his food because he read in an article that microwave radiation is even more dangerous than being exposed to UV light because of the high levels of energy in microwave radiation. You disagree with you friend and determine the energy of both types of electromagnetic radiation to prove him wrong. Assume that microwaves have a frequency of 520 MHz and that UV light has a frequency of approximately 780 THz. A. Could you tell if Angel is wrong without any mathematical process, given only the frequencies above? Explain B. Calculate the energy of photons of each type.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter7: Atomic Structure And Periodicity
Section: Chapter Questions
Problem 1RQ: Four types of electromagnetic radiation (EMR) are ultraviolet, microwaves, gamma rays, and visible....
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The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
Question
Transcribed Image Text:2. You are hanging out with your friend Angel, and you decided to warm up some snacks in the
microwave. Angle then tells you that he doesn't microwave his food because he read in an article that
microwave radiation is even more dangerous than being exposed to UV light because of the high levels
of energy in microwave radiation. You disagree with you friend and determine the energy of both types
of electromagnetic radiation to prove him wrong. Assume that microwaves have a frequency of 520
MHz and that UV light has a frequency of approximately 780 THz.
A. Could you tell if Angel is wrong without any mathematical process, given only the frequencies
above? Explain
B. Calculate the energy of photons of each type.
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