2. You are hanging out with your friend Angel, and you decided to warm up some snacks in the microwave. Angle then tells you that he doesn't microwave his food because he read in an article that microwave radiation is even more dangerous than being exposed to UV light because of the high levels of energy in microwave radiation. You disagree with you friend and determine the energy of both types of electromagnetic radiation to prove him wrong. Assume that microwaves have a frequency of 520 MHz and that UV light has a frequency of approximately 780 THz. A. Could you tell if Angel is wrong without any mathematical process, given only the frequencies above? Explain B. Calculate the energy of photons of each type.
Electronic Transitions and Spectroscopy
The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
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