2. Which of the following matrix can be covariance matrix and explain your results. 10 3 1 10 5 2 --- A = 2 50 B = 5 31 1 02 2 1 2 10 5 2 52 3 3 32

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Question 2:** Which of the following matrices can be a covariance matrix? Explain your results.

Matrices given:

Matrix \( A \):
\[
A = \begin{bmatrix} 
10 & 3 & 1 \\ 
2 & 5 & 0 \\ 
1 & 0 & 2 
\end{bmatrix}
\]

Matrix \( B \):
\[
B = \begin{bmatrix} 
10 & 5 & 2 \\ 
5 & 3 & 1 \\ 
2 & 1 & 2 
\end{bmatrix}
\]

Matrix \( C \):
\[
C = \begin{bmatrix} 
10 & 5 & 2 \\ 
5 & 3 & 3 \\ 
2 & 3 & 2 
\end{bmatrix}
\]

**Explanation:**

A covariance matrix must satisfy the following conditions:
- It is symmetric, meaning the element at row \( i \), column \( j \) must be equal to the element at row \( j \), column \( i \) for all \( i \) and \( j \).
- It is positive semidefinite, meaning for any non-zero vector \( x \), the product \( x^T A x \geq 0 \).

To determine which of these matrices could be a covariance matrix, you can check for symmetry and compute the eigenvalues to ensure they are non-negative for positive semidefiniteness.
Transcribed Image Text:**Question 2:** Which of the following matrices can be a covariance matrix? Explain your results. Matrices given: Matrix \( A \): \[ A = \begin{bmatrix} 10 & 3 & 1 \\ 2 & 5 & 0 \\ 1 & 0 & 2 \end{bmatrix} \] Matrix \( B \): \[ B = \begin{bmatrix} 10 & 5 & 2 \\ 5 & 3 & 1 \\ 2 & 1 & 2 \end{bmatrix} \] Matrix \( C \): \[ C = \begin{bmatrix} 10 & 5 & 2 \\ 5 & 3 & 3 \\ 2 & 3 & 2 \end{bmatrix} \] **Explanation:** A covariance matrix must satisfy the following conditions: - It is symmetric, meaning the element at row \( i \), column \( j \) must be equal to the element at row \( j \), column \( i \) for all \( i \) and \( j \). - It is positive semidefinite, meaning for any non-zero vector \( x \), the product \( x^T A x \geq 0 \). To determine which of these matrices could be a covariance matrix, you can check for symmetry and compute the eigenvalues to ensure they are non-negative for positive semidefiniteness.
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