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2. What is the theoretical yield if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0mL 5.50 mol·L-1 H2SO, and 4.50 g of Cu are used to prepare CuSO, 5 H2O?

2. What is the theoretical yield if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0mL 5.50 mol·L-1 H2SO, and 4.50 g of Cu are used to prepare CuSO, 5 H2O?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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5.4 Post-Lab Questions 1. Which reactant is the limiting reagent if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0 mL of 5.50 mol·L-1 H,SO, and 4.50 g of Cu are used to prepare CUSO4 ·5 H2O? | 2. What is the theoretical yield if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0mL 5.50 mol·L-1 H,SO, and 4.50 g of Cu are used to prepare CUSO, 5 H,O? 3. Using your answer from above determine the percent yield for that reaction if the actual yield of CUSO̟ · 5 H2O is 2.7 g. 4 4. (a) If 7.50 g of Cu is allowed to react using an excess of acids, what is the theoret- ical yield of CUSO4 ·5 H2O? (b) If the total volume of the solution is 40.0 mL, what is th mass of of CUSO4 ·5 H,O can dissolve? Assume that the solubility of CuSO 5 H20 in the reaction solu- tion from which it is crystallized is 45.0 g per 100 mL solution (i.e., a maximum of 45 g of product will dissolve in 100 mL of reaction solution). 4 (c) What mass of CuSO, 5 H,O would be crystallized (i.e. would not dissolve)? (d) How could you increase the percent yield during crystallization? 5. Predict the effect of using 2.00 g of Cu instead of 1.28 g in the preparation of CuSO, - 5 H,O if the volumes and concentrations of acids are the same as are used in this experiment. How would the actual yield be affected? The theoretical yield? 4
Transcribed Image Text:5.4 Post-Lab Questions 1. Which reactant is the limiting reagent if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0 mL of 5.50 mol·L-1 H,SO, and 4.50 g of Cu are used to prepare CUSO4 ·5 H2O? | 2. What is the theoretical yield if 8.00 mL of 3.50 mol·L-1 HNO3, 10.0mL 5.50 mol·L-1 H,SO, and 4.50 g of Cu are used to prepare CUSO, 5 H,O? 3. Using your answer from above determine the percent yield for that reaction if the actual yield of CUSO̟ · 5 H2O is 2.7 g. 4 4. (a) If 7.50 g of Cu is allowed to react using an excess of acids, what is the theoret- ical yield of CUSO4 ·5 H2O? (b) If the total volume of the solution is 40.0 mL, what is th mass of of CUSO4 ·5 H,O can dissolve? Assume that the solubility of CuSO 5 H20 in the reaction solu- tion from which it is crystallized is 45.0 g per 100 mL solution (i.e., a maximum of 45 g of product will dissolve in 100 mL of reaction solution). 4 (c) What mass of CuSO, 5 H,O would be crystallized (i.e. would not dissolve)? (d) How could you increase the percent yield during crystallization? 5. Predict the effect of using 2.00 g of Cu instead of 1.28 g in the preparation of CuSO, - 5 H,O if the volumes and concentrations of acids are the same as are used in this experiment. How would the actual yield be affected? The theoretical yield? 4
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