### Determining the Equivalent Capacitance of Capacitors#### Question:2. What is the equivalent capacitance of the three capacitors in the figure?#### Diagram Explanation:The diagram below shows a combination of three capacitors. - Capacitor 1 has a capacitance of \(20 \mu F\).- Capacitor 2 has a capacitance of \(30 \mu F\).- Capacitor 3 has a capacitance of \(25 \mu F\).The diagram illustrates a setup where the \(20 \mu F\) and \(30 \mu F\) capacitors are arranged in parallel, and this parallel combination is in series with the \(25 \mu F\) capacitor.#### Calculations:1. **Parallel Combination:** The total capacitance \(C_{parallel}\) of capacitors in parallel is given by: \[ C_{parallel} = C_1 + C_2 \] For the \(20 \mu F\) and \(30 \mu F\) capacitors: \[ C_{parallel} = 20 \mu F + 30 \mu F = 50 \mu F \]2. **Series Combination:** The equivalent capacitance \(C_{eq}\) of capacitors in series is given by: \[ \frac{1}{C_{eq}} = \frac{1}{C_{parallel}} + \frac{1}{C_3} \] Substituting the values: \[ \frac{1}{C_{eq}} = \frac{1}{50 \mu F} + \frac{1}{25 \mu F} = \frac{1}{50} + \frac{1}{25} = \frac{1 + 2}{50} = \frac{3}{50} \] Therefore, \[ C_{eq} = \frac{50}{3} \approx 16.67 \mu F \]#### Conclusion:The equivalent capacitance of the three capacitors in the given configuration is approximately \(16.67 \mu F\).

We have to find the equivalent capacitance of the capacitors.Taking Here C1 and C2 are in seriesFor…

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2. What is the equivalent capacitance of the three capacitors in the figure? 20 μF 30 με I 25 µF

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

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