2. Water is being heated in a kettle. At time t seconds, the temperature of water is T°C. The rate of increase of the water temperature is modelled as follows: k(120 – T), k=0.011 dt sec Given T = 20°C when t = 0, solve the differential equation and find the time required to reach 90°C of temperature.

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2. Water is being heated in a kettle. At time t seconds, the temperature of water is T°C.
The rate of increase of the water temperature is modelled as follows:
dT
- = k(120 – T), k=0.01 1
dt
sec
Given T = 20°C when t = 0, solve the differential equation and find the time required
to reach 90°C of temperature.
Transcribed Image Text:2. Water is being heated in a kettle. At time t seconds, the temperature of water is T°C. The rate of increase of the water temperature is modelled as follows: dT - = k(120 – T), k=0.01 1 dt sec Given T = 20°C when t = 0, solve the differential equation and find the time required to reach 90°C of temperature.
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