2. Verify that det(AB) = det(A)det(B) forthe following: -2 3 [1 0 2] a) A=-2 3 1 B= 3 -2 5| 1 2 1 3 Г2 3 [3 0 b) A= 0 3 2 B= 4 5 0 0 0 -4 2 1 -2 а 1 B b a 3. Show that = (b- a)(c- a)(b- c). This deteminant is called C Vandermonde determinant.
2. Verify that det(AB) = det(A)det(B) forthe following: -2 3 [1 0 2] a) A=-2 3 1 B= 3 -2 5| 1 2 1 3 Г2 3 [3 0 b) A= 0 3 2 B= 4 5 0 0 0 -4 2 1 -2 а 1 B b a 3. Show that = (b- a)(c- a)(b- c). This deteminant is called C Vandermonde determinant.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
answer the ff. 2 and 3
![2. Verify that det(AB) = det(A)det(B) for the following:
-2 31
1
[1 0 2]
а) А-D —2 3
1
В- 3 -2 5
1
2
1
3
Г2 3
6.
[3 0 0
b) A= 0 3 2
B= 4 5
0 0 -4
2 1 -2
a
a
3. Show that
B b
- (b-а)(с-а)(b- с).
This determinant is called
Vandermonde determinant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2437cd6d-d356-47be-9f36-bb1d16233559%2Ff643e265-aaa0-457b-9fb5-b3347bb66052%2F3v2std_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Verify that det(AB) = det(A)det(B) for the following:
-2 31
1
[1 0 2]
а) А-D —2 3
1
В- 3 -2 5
1
2
1
3
Г2 3
6.
[3 0 0
b) A= 0 3 2
B= 4 5
0 0 -4
2 1 -2
a
a
3. Show that
B b
- (b-а)(с-а)(b- с).
This determinant is called
Vandermonde determinant.
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