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2. Using Loop Analysis by applying KVL, find the current through all the resistors in the given circuit. R, R3 Iksz 15V Iov 2

2. Using Loop Analysis by applying KVL, find the current through all the resistors in the given circuit. R, R3 Iksz 15V Iov 2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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note: R2 is only (5 Ohm )not k ohm
2. Using Loop Analysis by applying KVL, find the current through all the resistors in the given circuit. R, Rg lov Ra
Transcribed Image Text:2. Using Loop Analysis by applying KVL, find the current through all the resistors in the given circuit. R, Rg lov Ra
Example 1.14 Find the current through all resistors in the circuit given in Fig.1.27. FIG.1.27 Example 1.14 12 62 20 > R 10V 5V E1 Solution Step 1: Mark the mesh currents as shown in Fig.1.27 Step 2 : Obtain the matrix representation by inspection. R, +R, -R, [E, -E, -R, R, +R,I, Step 3: Obtain the solution using Cramer's rule. A= - 6 = 56– 36 = 20 8 Note : this for example please solve same this steps DC Circuis 29 -5 -6 A, = 10 -40 -(-60) = 20 8 - 5 = 70 – 30 = 40 A, = 20 -= 1A 20 I = A, I, = 40 = 2 A 20 %3D
Transcribed Image Text:Example 1.14 Find the current through all resistors in the circuit given in Fig.1.27. FIG.1.27 Example 1.14 12 62 20 > R 10V 5V E1 Solution Step 1: Mark the mesh currents as shown in Fig.1.27 Step 2 : Obtain the matrix representation by inspection. R, +R, -R, [E, -E, -R, R, +R,I, Step 3: Obtain the solution using Cramer's rule. A= - 6 = 56– 36 = 20 8 Note : this for example please solve same this steps DC Circuis 29 -5 -6 A, = 10 -40 -(-60) = 20 8 - 5 = 70 – 30 = 40 A, = 20 -= 1A 20 I = A, I, = 40 = 2 A 20 %3D
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