2. True/False: If F, G are vector fields and V × F = V × G, then F = G. (Justify your answer by using the properties of curl.) 3. True/False: If F is conservative then V · F = 0. (Justify your answer.)
2. True/False: If F, G are vector fields and V × F = V × G, then F = G. (Justify your answer by using the properties of curl.) 3. True/False: If F is conservative then V · F = 0. (Justify your answer.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please answer question 2 and 3 for this homework. Thanks
![1. True/False: V (V × F) = 0. (Justify your answer by showing it is true or false
for vector fields of the form F Fi+ Gj.)
2. True/False: If F, G are vector fields and V × F = V x G, then F = G. (Justify
your answer by using the properties of curl.)
3. True/False: If F is conservative then V F 0. (Justify your answer.)
4. True/False: curl(divF)) is not a meaningful expression. (Justify your answer.)
5. Using Stokes' theorem, find I = | [,(V × F)-ndo , where F
and S is the portion of the surface 2.x -+ y + z = 2 above the first octant and n is
the unitary normal vector to the surface, with non-negative z component.
yi + rj+(y+ z) k](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41a1af84-f79e-495e-9bf6-e155c46aa5b8%2F5f24a798-e423-4fa3-a646-6637cb915b83%2F8mzgpwd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. True/False: V (V × F) = 0. (Justify your answer by showing it is true or false
for vector fields of the form F Fi+ Gj.)
2. True/False: If F, G are vector fields and V × F = V x G, then F = G. (Justify
your answer by using the properties of curl.)
3. True/False: If F is conservative then V F 0. (Justify your answer.)
4. True/False: curl(divF)) is not a meaningful expression. (Justify your answer.)
5. Using Stokes' theorem, find I = | [,(V × F)-ndo , where F
and S is the portion of the surface 2.x -+ y + z = 2 above the first octant and n is
the unitary normal vector to the surface, with non-negative z component.
yi + rj+(y+ z) k
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