### Confidence Interval Estimation**Question 2:**The z value for a 94% confidence interval estimation is _____.**Options:**- ○ 1.96- ○ 2.33- ○ 1.645- ○ 1.88In this question, students are asked to identify the correct z-value associated with a 94% confidence interval. Z-values are critical in determining the range within which we expect a population parameter to lie, based on a sample statistic. Choosing the correct z-value is essential for accurate statistical inference.

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Answered: 2. The z value for a 94% confidence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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f. A sample of 60 Grade 10 students' ages was obtained to estimate the mean lof all Grade 9 students. i = 15.2 years and the population variance is 15. a. What is the point estimate for u? b. Find the 95% confidence interval for u. c. Find the 99% confidence interval for u. d. What conclusions can you make based on each estimate?
If the number of smokers in a sample of 160 students selected from university A is 56 and the number of smokers in a sample of 60 students selected from university B is 16. Then the 98% confidence interval for the difference between proportions of smokers in the two universities (PB-PA) is closest to a. (-0.0942,-0.0724) b. None of these c.(-0.2240,0.0572) d. (-0.2420,0.0758) e. (-0.0929,-0.0737)
The Za/2 value for a confidence interval is found as 1.29. What is the confidence level? Select one: а. 80% b. 70% c. 90% d. 83% е. 75%
A researcher is attempting to calculate a 95% confidence interval for the mean average wingspan of Statsian Swallows in a particular rainforest. They take a sample and find that of the 16 swallows surveyed, the mean average was 3.14 inches and the standard deviation was 0.2 inches. What is the 95% confidence interval for this sample?
A 90% confidence interval for p is given as (0.26,0.54). How large was the sample used to construct this interval? (Round up to the nearest observation.)
IMR in Singapore. The infant mortality rate (IMR) is the number of infant deaths per 1000 live births. Suppose that you have been commissioned to estimate the IMR in Singapore. From a random sample of 1109 live births in Singapore, you find that 0.361% of them resulted in infant deaths. You next find a 90% confidence interval: or 0.000647 to 0.00657. You then conclude, “I can be 90% confident that the IMR in Singapore is somewhere between 0.647 and 6.57.” How did you do?
If n = 590 and ˆp = 0.94, construct a 95% confidence interval.Give your answers to three decimals __< p < __
Given a confidence interval {21.98, 28.64 and a mean of 25.31, the margin of error is 6.66. True or False
Assume that the 95% confidence interval for mean=9 and standard devaition=20. For a particular data, the standardized value z = 2.73. We can say that: Select one: a. The data with standardized value 2.73 does not belong to the confidence interval and the value is less than the average. b. The data with standardized value 2.73 does not belong to the confidence interval and the value is greater than the average. c. Cannot interpret the z-value information provided. d. The data with standardized value 2.73 if it belongs to the confidence interval and the value is less than the average. e. The data with standardized value 2.73 if it belongs to the confidence interval and the value is greater than the average.
Obesity is defined as a body mass index (BMI) of 30 kg/m2 or more. A 95% confidence interval for the percentage of U.S. adults aged 20 years and over who were obese was found to be 20.26% to 29.8%. What was the sample size?
What if we're able to use a normal model. To construct a 95% Confidence Interval, we use the following formula: p hat ± ME for 95% CI If p hat = 0.38 and ME for 95% CI = 0.096, what is CI? Keep the numbers in 3 decimal places. Put the two numbers in ( ) and use a comma, then a space between the two numbers.

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2. The z value for a 94% confidence interval estimation is 1.96 2.33 1.645 1.88