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2. The van is traveling at a constant speed over the hill described by the function shown. At a x position of 50 ft, the magnitude of the acceleration is 1.5 ft/s?. What is the speed of the vehicle at this point? Answer → 22.7 ft/s 15 ft y = (-1,5 (10~³) x² + 15) ft 100 ft 12 PROB_084

2. The van is traveling at a constant speed over the hill described by the function shown. At a x position of 50 ft, the magnitude of the acceleration is 1.5 ft/s?. What is the speed of the vehicle at this point? Answer → 22.7 ft/s 15 ft y = (-1,5 (10~³) x² + 15) ft 100 ft 12 PROB_084

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2. The van is traveling at a constant speed over the hill described by the function shown. At a x position of 50 ft, the magnitude of the acceleration is 1.5 ft/s?. What is the speed of the vehicle at this point? Answer → 22.7 ft/s y = (-1,5 (10–³)x² + 15) ft 15 ft 100 ft 12_PROB_084 Capyrsht neus aor tucation I Rgra Reaerved
Transcribed Image Text:2. The van is traveling at a constant speed over the hill described by the function shown. At a x position of 50 ft, the magnitude of the acceleration is 1.5 ft/s?. What is the speed of the vehicle at this point? Answer → 22.7 ft/s y = (-1,5 (10–³)x² + 15) ft 15 ft 100 ft 12_PROB_084 Capyrsht neus aor tucation I Rgra Reaerved
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