Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Physics Problem: Heat Transfer Calculation**
**Problem Statement:**
The specific heat of iron is \(0.4494 \, \text{J/g} \cdot °\text{C}\). How much heat is transferred when a \(4.7 \, \text{kg}\) piece of iron is cooled from \(180 \, °\text{C}\) to \(13 \, °\text{C}\)?
---
To solve this problem, consider using the formula for heat transfer:
\[
q = m \cdot c \cdot \Delta T
\]
Where:
- \(q\) is the heat transferred (in Joules),
- \(m\) is the mass of the substance (in grams),
- \(c\) is the specific heat capacity (in Joules per gram per degree Celsius),
- \(\Delta T\) is the change in temperature (in degrees Celsius).
Convert the mass from kilograms to grams:
\[
4.7 \, \text{kg} = 4700 \, \text{g}
\]
Calculate the change in temperature:
\[
\Delta T = T_{\text{final}} - T_{\text{initial}} = 13 \, °\text{C} - 180 \, °\text{C} = -167 \, °\text{C}
\]
Substitute these values into the formula to find the heat transferred.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01a3e116-2316-49e5-843e-67526366cfac%2Fc1fc99bd-8bf7-4b9e-b7cf-20ee3b465feb%2Fzoi1yg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Problem: Heat Transfer Calculation**
**Problem Statement:**
The specific heat of iron is \(0.4494 \, \text{J/g} \cdot °\text{C}\). How much heat is transferred when a \(4.7 \, \text{kg}\) piece of iron is cooled from \(180 \, °\text{C}\) to \(13 \, °\text{C}\)?
---
To solve this problem, consider using the formula for heat transfer:
\[
q = m \cdot c \cdot \Delta T
\]
Where:
- \(q\) is the heat transferred (in Joules),
- \(m\) is the mass of the substance (in grams),
- \(c\) is the specific heat capacity (in Joules per gram per degree Celsius),
- \(\Delta T\) is the change in temperature (in degrees Celsius).
Convert the mass from kilograms to grams:
\[
4.7 \, \text{kg} = 4700 \, \text{g}
\]
Calculate the change in temperature:
\[
\Delta T = T_{\text{final}} - T_{\text{initial}} = 13 \, °\text{C} - 180 \, °\text{C} = -167 \, °\text{C}
\]
Substitute these values into the formula to find the heat transferred.
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