**Physics Problem: Heat Transfer Calculation****Problem Statement:**The specific heat of iron is \(0.4494 \, \text{J/g} \cdot °\text{C}\). How much heat is transferred when a \(4.7 \, \text{kg}\) piece of iron is cooled from \(180 \, °\text{C}\) to \(13 \, °\text{C}\)?---To solve this problem, consider using the formula for heat transfer:\[q = m \cdot c \cdot \Delta T\]Where:- \(q\) is the heat transferred (in Joules),- \(m\) is the mass of the substance (in grams),- \(c\) is the specific heat capacity (in Joules per gram per degree Celsius),- \(\Delta T\) is the change in temperature (in degrees Celsius).Convert the mass from kilograms to grams:\[4.7 \, \text{kg} = 4700 \, \text{g}\]Calculate the change in temperature:\[\Delta T = T_{\text{final}} - T_{\text{initial}} = 13 \, °\text{C} - 180 \, °\text{C} = -167 \, °\text{C}\]Substitute these values into the formula to find the heat transferred.

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Answered: 2. The specific heat of iron is 0.4494…

2. The specific heat of iron is 0.4494 J/g x °C. How much heat is transferred when a 4.7 kg piece of iron is cooled from 180 °C to 13 °C?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Physics Problem: Heat Transfer Calculation**

**Problem Statement:**

The specific heat of iron is \(0.4494 \, \text{J/g} \cdot °\text{C}\). How much heat is transferred when a \(4.7 \, \text{kg}\) piece of iron is cooled from \(180 \, °\text{C}\) to \(13 \, °\text{C}\)?

---

To solve this problem, consider using the formula for heat transfer:

\[
q = m \cdot c \cdot \Delta T
\]

Where:
- \(q\) is the heat transferred (in Joules),
- \(m\) is the mass of the substance (in grams),
- \(c\) is the specific heat capacity (in Joules per gram per degree Celsius),
- \(\Delta T\) is the change in temperature (in degrees Celsius).

Convert the mass from kilograms to grams:
\[
4.7 \, \text{kg} = 4700 \, \text{g}
\]

Calculate the change in temperature:
\[
\Delta T = T_{\text{final}} - T_{\text{initial}} = 13 \, °\text{C} - 180 \, °\text{C} = -167 \, °\text{C}
\]

Substitute these values into the formula to find the heat transferred.

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