2. The potential difference between points A and B (Fig. 2) is U = 15 V. The capacitance of the first capacitor is C1 = 4 x 10-6 F and that of the second C2 = 8 x 10-6 F. Find the charge and the potential difference on %3D the plates of each capacitor. C2 A Figure 2.
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- bIP A parallel-plate capacitor has plates with an area of 1.1×10-2 m² and a separation of 0.83 mm. The space between the plates is filled with a dielectric whose dielectric constant is 1.9. ▾ Part A What is the potential difference between the plates when the charge on the capacitor plates is 4.0 μC ? Express your answer using two significant figures. 15. ΑΣΦ V= Submit ▾ Part B O Increase O Decrease Will your answer to part A increase, decrease, or stay the same if the dielectric constant is increased? O Stay the same Submit Request Answer Part D Part C Complete previous part(s) V= Request Answer Submit B ? Calculate the potential difference for the case where the dielectric constant is 4.1. Express your answer using two significant figures. VE| ΑΣΦ Request Answer V ? VOnly Part C
- . A parallel-plate capacitor is made of two circular plates, each with a diameter of 2.50x10^-3 m. The plates of this capacitor are separated by a space of 1.40x10^-4 m. How much charge will be stored on each plate of this capacitor when it is connected across a potential difference of 0.12V? A. 3.7x10^-8 µC B. 4.2x10^-8 µC C. 5.6x10^-8 µC D. 6.1x10^-8 µC1.0 μF capacitor has a potential difference of 6.0 V applied across its plates. a.How much energy is stored in the capacitor? b.If a sheet of mica (dielectric constant = 4.0) is now inserted between the plates, how much energy is now stored in the capacitor. Please give full reasoning to the answer and please explain each of the steps.The electric potential increases from 100 V to 800 V from the bottom plate to the top plate of a parallel-plate capacitor. a. What is the magnitude of the change in potential energy of a −3 × 10^−4 C charge that is moved from the bottom plate to the top plate? b. Does the potential energy increase or decrease in this process?
- 5. A capacitor is charged by a battery. It may or may not have been removed from this battery. A dielectric is then either inserted or removed from between the plates. The capacitance increased by a factor of 5 and the charge across the plates increased by a factor of 5. a. Was the capacitor on or off the battery? Explain. b. Was the dielectric inserted or removed from between the plates? Explain.Charge q is fired through a small hole in the positive plate of a capacitor, as shown.a. If q is a positive charge, does it speed up or slow down inside the capacitor? Answer this question twice: (i) Using the concept of force. (ii) Using the concept of energy.b. Repeat part a if q is a negative charge.Part A The voltage across a 4 μF capacitor increases by 48 V. If the final charge on the capacitor is 507 μC, determine the initial charge. Q₁ = Part B Two parallel plates each have a charge magnitude of 601 nC. Between the plates is a dielectric with K = 86. Additionally, the E-field between the plates is 7.81x105 V/m. Determine the area of each plate. A= Part C A capacitor with no dielectric has an E-field of 88 kV/mm between the plates. The area of each plate is 46.3 cm² and the voltage across the capacitor is 1.5 V. Determine the capacitance. C=
- A 3.50 cm in diameter parallel plate capacitor has a 1.50 mm spacing. The electric field inside the capacitor is 3 x 105 V/m.a. What is the potential different across the capacitor?b. How much charge is on each plate?c. If the charge on the plates remains the same as the plates are pulled apart will the voltage difference Increase decrease or stay the same?Two 2.10 cm x 2.10 cm plates that form a parallel- plate capacitor are charged to ±0.708 nC. ▾ Part A What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm? Express your answer with the appropriate units. E= Value Submit Request Answer Part B ? Units What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ? Express your answer with the appropriate units. HÅ V = Value Units Submit Request Answer Part C ? What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. με E = Value Units Submit Request Answer Part D ? What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. ΜΑ ? V = Value Units Submit Request Answer Provide FeedbackIn (Figure 1), C1 = 6.00 pF, C2 = 3.00 μF, and C3 = 5.00 μF. The capacitor network is connected to an applied potential Vab After the charges on the capacitors have reached their final values, the charge on C2 is 30.0 μC. Figure b C₁ C3 d 1 of 1 Part A What is the charge on capacitor C1? Express your answer with the appropriate units. Q1 = Submit Part B Q3 = Submit Part C 123+ What is the charge on capacitor C3? Express your answer with the appropriate units. Vab= Value Submit 123+ Request Answer Value ( 3 ? 123+ Provide Feedback Units What is the applied voltage Vab? Express your answer with the appropriate units. Value Request Answer 3 CE? Units CE ? Units Request Answer G