2. The position function of a moving object is s(t)= t³(3-t), 120 in metres, at time t, in seconds. a. Calculate the object's velocity and acceleration at any time t. b. After how many seconds does the object stop? c. When does the motion of the object change direction? d. When does the object return to its original position?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Question

Please help me is this correct for the question. And please complete part d) show all your work

2. The position function of a moving object is s(t)= t³(3-t), r=0 in metres, at time 7, in seconds.
a. Calculate the object's velocity and acceleration at any time .
b. After how many seconds does the object stop?
c. When does the motion of the object change direction?
d. When does the object return to its original position?
૫૦૦ ૩૧/૧૦/H
Transcribed Image Text:2. The position function of a moving object is s(t)= t³(3-t), r=0 in metres, at time 7, in seconds. a. Calculate the object's velocity and acceleration at any time . b. After how many seconds does the object stop? c. When does the motion of the object change direction? d. When does the object return to its original position? ૫૦૦ ૩૧/૧૦/H
#2 s(t)=+³ (3-4), (20
a) Velocity
V=
ds
dt = +²³(-1) = 5t4 (3-6)
Acceleration
4
-6t³ + 15t" m/s
ds
A = d² ² = a (-66² + 15 (4)
Hence,
d
= (-61³) + (1514)
3
= - 30t4 + 60€ ³ m/s
b) Let I be the time when the object stop, so v=0 when t = I
0 = -6+³ + 1ST" (using part (a))
=) T² (-6T +15) = (
=) -6 + 15 = 0 (;. T # ()
15. 5
T²
=> √ = = 16² = ²2²2²2² = 4.5
The required time is 4.5 sec for the object to stop
The motion of the object changes its direction when the
acceleration becomes 0.
dsz
Let I' be the time when the object changes its directich so,
बदर
3
0$ = = 0 => -30T¹² +
60T1³ = 0 (use part (a))
= 0 => -30T₁²4 + 6071³ = 0 (0₂
¹1=T'
=> T'3 (-30T' +60) = (
=2-307/ + 60 = 0 (²₁ T² # 0)
=> T² =2
The required time is 2 for the motion of the object to change
direction
Hebre
Transcribed Image Text:#2 s(t)=+³ (3-4), (20 a) Velocity V= ds dt = +²³(-1) = 5t4 (3-6) Acceleration 4 -6t³ + 15t" m/s ds A = d² ² = a (-66² + 15 (4) Hence, d = (-61³) + (1514) 3 = - 30t4 + 60€ ³ m/s b) Let I be the time when the object stop, so v=0 when t = I 0 = -6+³ + 1ST" (using part (a)) =) T² (-6T +15) = ( =) -6 + 15 = 0 (;. T # () 15. 5 T² => √ = = 16² = ²2²2²2² = 4.5 The required time is 4.5 sec for the object to stop The motion of the object changes its direction when the acceleration becomes 0. dsz Let I' be the time when the object changes its directich so, बदर 3 0$ = = 0 => -30T¹² + 60T1³ = 0 (use part (a)) = 0 => -30T₁²4 + 6071³ = 0 (0₂ ¹1=T' => T'3 (-30T' +60) = ( =2-307/ + 60 = 0 (²₁ T² # 0) => T² =2 The required time is 2 for the motion of the object to change direction Hebre
Expert Solution
steps

Step by step

Solved in 3 steps with 9 images

Blurred answer
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,