2. The Polynomial P is a function of x. The graph of P has four zeros at -2, 3, 2, and 13 -Which Functions could represent P? 2 3. P(x) = (x-2) (3x + ¹) (x+2) (4x+13) □P(X) = (x+2) (3x-1) (x-2) (4x+13) OP(x)=(x-2)(x+3)(x+2) OP(x) = (x+2)(x-3)(x-2) DOP(x) = (x+2)(x-3)(x-2)² (4x-13) (x + 13/4) (x-13/21),
2. The Polynomial P is a function of x. The graph of P has four zeros at -2, 3, 2, and 13 -Which Functions could represent P? 2 3. P(x) = (x-2) (3x + ¹) (x+2) (4x+13) □P(X) = (x+2) (3x-1) (x-2) (4x+13) OP(x)=(x-2)(x+3)(x+2) OP(x) = (x+2)(x-3)(x-2) DOP(x) = (x+2)(x-3)(x-2)² (4x-13) (x + 13/4) (x-13/21),
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![2 The Polynomial P is a function of x. The graph
of P has four zeros at -2, 3, 2, and 13
-Which Functions could represent P?
S
3.JP(x) = (x-2) (3x+¹) (x+2) (4x+13)
OP(x) = (x+2) (3x-1) (x-2) (4x+13)
DOP(X)=(x-2) (x+3)(x+2) (x + 13/4)
□P(x) = (x+2)(x-1/3)(x-2) (x-13/41).
P(X) = (x+2)(x-3)(x-2)² (4x-13)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F029c5c41-2442-494b-93d3-6efa82f27b91%2Fd770f6a4-d860-4c78-ad58-a55414c9b33f%2Fx2x6nda_processed.png&w=3840&q=75)
Transcribed Image Text:2 The Polynomial P is a function of x. The graph
of P has four zeros at -2, 3, 2, and 13
-Which Functions could represent P?
S
3.JP(x) = (x-2) (3x+¹) (x+2) (4x+13)
OP(x) = (x+2) (3x-1) (x-2) (4x+13)
DOP(X)=(x-2) (x+3)(x+2) (x + 13/4)
□P(x) = (x+2)(x-1/3)(x-2) (x-13/41).
P(X) = (x+2)(x-3)(x-2)² (4x-13)
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