2. The photoelectric attenuation coefficient in lead at 150 keV is 620x10-28 m²/atom. Assuming that all this coefficient arises from the K electrons, calculate the energy transfer coefficient (in m-¹). Also, express in m²/kg. For lead, there are 2.907x1024 atom/kg, K electron binding energy = 88 keV in lead, density of lead = 11360 kg/m³.
2. The photoelectric attenuation coefficient in lead at 150 keV is 620x10-28 m²/atom. Assuming that all this coefficient arises from the K electrons, calculate the energy transfer coefficient (in m-¹). Also, express in m²/kg. For lead, there are 2.907x1024 atom/kg, K electron binding energy = 88 keV in lead, density of lead = 11360 kg/m³.
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
Transcribed Image Text:2. The photoelectric attenuation coefficient in lead at 150 keV is 620x1028
m?/atom. Assuming that all this coefficient arises from the K electrons,
calculate the energy transfer coefficient (in m-l). Also, express in m2/kg.
For lead, there are 2.907x1024 atom/kg, K electron binding energy = 88 keV
in lead, density of lead = |1360 kg/m³.
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