2. The phasor of an AC voltage is given as V, -10-10V. Assuming that co= 5 rad/sec, this voltage in the time-domain is: ((a))v (1)-10cos(5t-45°) V (b) v(t)-10√2cos(5r) V (c) v.(t)=10sin(51) V (d) v (t)=10√2cos(5t-45°) V
2. The phasor of an AC voltage is given as V, -10-10V. Assuming that co= 5 rad/sec, this voltage in the time-domain is: ((a))v (1)-10cos(5t-45°) V (b) v(t)-10√2cos(5r) V (c) v.(t)=10sin(51) V (d) v (t)=10√2cos(5t-45°) V
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2. The phasor of an AC voltage is given as V, -10-10V. Assuming that = 5 rad/sec,
this voltage in the time-domain is:
((a))v. (1)-10cos(51-45°) V
(b) v (t)=10√2cos(5r) V
(c) v. (1)-10sin(51) V
(d) v (t)=10√2cos(51-45°) V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d9c6f74-1705-4000-b131-f6dda99da1a0%2F7d24800f-2240-47d7-b746-0302450b8f9a%2Fd1w9t4k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:se
2. The phasor of an AC voltage is given as V, -10-10V. Assuming that = 5 rad/sec,
this voltage in the time-domain is:
((a))v. (1)-10cos(51-45°) V
(b) v (t)=10√2cos(5r) V
(c) v. (1)-10sin(51) V
(d) v (t)=10√2cos(51-45°) V
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