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2. The phase portrait of the system = -y, d= consists of DA. ellipses OB. circles OC. parabolas OD. lines through the origin OE. hyperbolas OF. none of the above

2. The phase portrait of the system = -y, d= consists of DA. ellipses OB. circles OC. parabolas OD. lines through the origin OE. hyperbolas OF. none of the above

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2 nd part question first part answer is  E please solve second part and give solution

Problem 6. Select the correct answer for each question (only one answer per question). If you select an answer and then change your mind, make sure you uncheck your previous answer. 1. Find the most suitable form (with the minimum amount of terms) for a particular solution of y" +9y=-6e4t+t sin(3t) if the method of undetermined coefficients is used. DA. yp= Aet + Bt sin(3t) OB. Yp = Aet + B sin(3t) + C cos(3t) OC. yp = Ate4t + Bt sin (3t) + Ct cos(3t) OD. Yp DE. Yp = Aet + (Bt+C) sin(3t) + (Dt + E) cos(3t) = Aet+t(Bt+ C) sin(3t) + t(Dt + E) cos(3t) OF. none of the above 2. The phase portrait of the system = DA. ellipses OB. circles OC. parabolas OD. lines through the origin OE. hyperbolas dy =-Y dt OF. none of the above Answer E = consists of:
Transcribed Image Text:Problem 6. Select the correct answer for each question (only one answer per question). If you select an answer and then change your mind, make sure you uncheck your previous answer. 1. Find the most suitable form (with the minimum amount of terms) for a particular solution of y" +9y=-6e4t+t sin(3t) if the method of undetermined coefficients is used. DA. yp= Aet + Bt sin(3t) OB. Yp = Aet + B sin(3t) + C cos(3t) OC. yp = Ate4t + Bt sin (3t) + Ct cos(3t) OD. Yp DE. Yp = Aet + (Bt+C) sin(3t) + (Dt + E) cos(3t) = Aet+t(Bt+ C) sin(3t) + t(Dt + E) cos(3t) OF. none of the above 2. The phase portrait of the system = DA. ellipses OB. circles OC. parabolas OD. lines through the origin OE. hyperbolas dy =-Y dt OF. none of the above Answer E = consists of:
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