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2. The matrices A and B, below, are row equivalent (so B is an echelon form of A): 1 3 4 -1 2 2 6 6 0-3 A = 3 9 3 6-3 3 9 0 9 0 1 3 4 -1 2 0 2-2 0 -1 0 0 0 0-3 0 000 0 (a) Find a basis for the column space of A. Explain your answer briefly. (b) Find a basis for the null space of A. Show your work.

2. The matrices A and B, below, are row equivalent (so B is an echelon form of A): 1 3 4 -1 2 2 6 6 0-3 A = 3 9 3 6-3 3 9 0 9 0 1 3 4 -1 2 0 2-2 0 -1 0 0 0 0-3 0 000 0 (a) Find a basis for the column space of A. Explain your answer briefly. (b) Find a basis for the null space of A. Show your work.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. The matrices A and B, below, are row equivalent (so B is an echelon form of A): 1 3 4 -1 2 2 6 6 0-3 A = 3 9 3 6-3 3 9 0 9 0 1 3 4 -1 2 0 2-2 0 -1 0 0 0 0-3 0 000 0 (a) Find a basis for the column space of A. Explain your answer briefly. (b) Find a basis for the null space of A. Show your work.
Transcribed Image Text:2. The matrices A and B, below, are row equivalent (so B is an echelon form of A): 1 3 4 -1 2 2 6 6 0-3 A = 3 9 3 6-3 3 9 0 9 0 1 3 4 -1 2 0 2-2 0 -1 0 0 0 0-3 0 000 0 (a) Find a basis for the column space of A. Explain your answer briefly. (b) Find a basis for the null space of A. Show your work.
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