2. The following data was collected as a solution was prepared. Mass unknown solute (g) Mass solvent (g) Tf(solvent) (°C) Tf(solution) (°C) kf(°C-kg/mol) 0.117 6.30 2.62 6.50 5.28 a. Calculate the AT, for the solution using equation (1) above. b. The solute is a nonelectrolyte. Using equation (2) above, find the molality of the solution. c. Calculate the moles of the unknown solute. d. Calculate the molar mass of the unknown solute.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter11: Properties Of Solutions
Section: Chapter Questions
Problem 7RQ: Vapor-pressure lowering is a colligative property, as are freezing-point depression and...
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### Freezing Point Depression Data

The following data was collected during the preparation of a solution:

| Mass unknown solute (g) | Mass solvent (g) | \( T_f \) (solvent) (°C) | \( T_f \) (solution) (°C) | \( k_f \) (°C·kg/mol) |
|-------------------------|------------------|------------------------|------------------------|--------------------------|
| 0.117                   | 5.28             | 6.30                   | 2.62                   | 6.50                     |

#### Tasks:
a. **Calculate the \(\Delta T_f\) for the solution using the equation given above.**
b. **The solute is a nonelectrolyte. Using the equation (2) above, find the molality of the solution.**
c. **Calculate the moles of the unknown solute.**
d. **Calculate the molar mass of the unknown solute.**

#### Explanation:
- **\(\Delta T_f\)** represents the change in freezing point of the solution.
- **Molality** is a measure of the number of moles of solute per kilogram of solvent.
- **Nonelectrolyte** implies that the solute does not dissociate into ions in the solution.
- **Moles of solute** can be calculated via the molality and mass data.
- **Molar mass** is the mass of one mole of a substance.

### Example Calculations:
1. **Calculate \(\Delta T_f\)**:
   \(\Delta T_f = T_f(\text{solvent}) - T_f(\text{solution}) = 6.30^\circ \text{C} - 2.62^\circ \text{C} = 3.68^\circ \text{C}\)

2. **Find the molality of the solution**:
   Using the formula: 
   \[
   \Delta T_f = k_f \cdot m
   \]
   where \( \Delta T_f \) is the freezing point depression, \( k_f \) is the freezing point depression constant, and \( m \) is the molality.
   \[
   3.68^\circ \text{C} = 6.50^\circ \text{C·kg/mol} \cdot m 
   \]
   Solving
Transcribed Image Text:### Freezing Point Depression Data The following data was collected during the preparation of a solution: | Mass unknown solute (g) | Mass solvent (g) | \( T_f \) (solvent) (°C) | \( T_f \) (solution) (°C) | \( k_f \) (°C·kg/mol) | |-------------------------|------------------|------------------------|------------------------|--------------------------| | 0.117 | 5.28 | 6.30 | 2.62 | 6.50 | #### Tasks: a. **Calculate the \(\Delta T_f\) for the solution using the equation given above.** b. **The solute is a nonelectrolyte. Using the equation (2) above, find the molality of the solution.** c. **Calculate the moles of the unknown solute.** d. **Calculate the molar mass of the unknown solute.** #### Explanation: - **\(\Delta T_f\)** represents the change in freezing point of the solution. - **Molality** is a measure of the number of moles of solute per kilogram of solvent. - **Nonelectrolyte** implies that the solute does not dissociate into ions in the solution. - **Moles of solute** can be calculated via the molality and mass data. - **Molar mass** is the mass of one mole of a substance. ### Example Calculations: 1. **Calculate \(\Delta T_f\)**: \(\Delta T_f = T_f(\text{solvent}) - T_f(\text{solution}) = 6.30^\circ \text{C} - 2.62^\circ \text{C} = 3.68^\circ \text{C}\) 2. **Find the molality of the solution**: Using the formula: \[ \Delta T_f = k_f \cdot m \] where \( \Delta T_f \) is the freezing point depression, \( k_f \) is the freezing point depression constant, and \( m \) is the molality. \[ 3.68^\circ \text{C} = 6.50^\circ \text{C·kg/mol} \cdot m \] Solving
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