2. The brakes on a 17,600 N car exert a stopping force of 650. N. The car's velocity changes from 25.0 m/s to 0 m/s. a) What is the car's mass? b) What was its initial momentum? c) What was the change in momentum for the car? d) How long does it take the braking force to bring the car to rest?

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### Physics Problem: Car Braking Analysis

#### Problem Statement:

The brakes on a 17,600 N car exert a stopping force of 650 N. The car's velocity changes from 25.0 m/s to 0 m/s.

**Questions:**
a) What is the car’s mass?
b) What was its initial momentum?
c) What was the change in momentum for the car?
d) How long does it take the braking force to bring the car to rest?

#### Solution Steps:

1. **Finding the Car’s Mass:**

    Given:
    - Weight (W) = 17,600 N
    - Acceleration due to gravity (g) ≈ 9.8 m/s²

    Using the formula for weight:
    \[
    W = m \cdot g
    \]
    
    Therefore:
    \[
    m = \frac{W}{g} = \frac{17,600 \text{ N}}{9.8 \text{ m/s}^2} = 1795.92 \text{ kg}
    \]

2. **Calculating the Initial Momentum:**

    Given:
    - Initial velocity (v) = 25.0 m/s

    Using the momentum formula:
    \[
    p = m \cdot v
    \]
    
    Therefore:
    \[
    p = 1795.92 \text{ kg} \cdot 25.0 \text{ m/s} = 44,898 \text{ kg m/s}
    \]

3. **Determining the Change in Momentum:**

    The car stops, hence the final velocity is 0 m/s. Thus, the change in momentum (\( \Delta p \)) is:
    \[
    \Delta p = p_{\text{final}} - p_{\text{initial}} = 0 \text{ kg m/s} - 44,898 \text{ kg m/s} = -44,898 \text{ kg m/s}
    \]

4. **Calculating the Time to Come to Rest:**

    Using Newton's second law:
    \[
    F = \Delta p / \Delta t
    \]
    
    Rearrange to solve for time (\( \Delta t \)):
    \[
    \Delta t = \frac{\Delta p}{F}
    \]

    Substitute the values:
Transcribed Image Text:### Physics Problem: Car Braking Analysis #### Problem Statement: The brakes on a 17,600 N car exert a stopping force of 650 N. The car's velocity changes from 25.0 m/s to 0 m/s. **Questions:** a) What is the car’s mass? b) What was its initial momentum? c) What was the change in momentum for the car? d) How long does it take the braking force to bring the car to rest? #### Solution Steps: 1. **Finding the Car’s Mass:** Given: - Weight (W) = 17,600 N - Acceleration due to gravity (g) ≈ 9.8 m/s² Using the formula for weight: \[ W = m \cdot g \] Therefore: \[ m = \frac{W}{g} = \frac{17,600 \text{ N}}{9.8 \text{ m/s}^2} = 1795.92 \text{ kg} \] 2. **Calculating the Initial Momentum:** Given: - Initial velocity (v) = 25.0 m/s Using the momentum formula: \[ p = m \cdot v \] Therefore: \[ p = 1795.92 \text{ kg} \cdot 25.0 \text{ m/s} = 44,898 \text{ kg m/s} \] 3. **Determining the Change in Momentum:** The car stops, hence the final velocity is 0 m/s. Thus, the change in momentum (\( \Delta p \)) is: \[ \Delta p = p_{\text{final}} - p_{\text{initial}} = 0 \text{ kg m/s} - 44,898 \text{ kg m/s} = -44,898 \text{ kg m/s} \] 4. **Calculating the Time to Come to Rest:** Using Newton's second law: \[ F = \Delta p / \Delta t \] Rearrange to solve for time (\( \Delta t \)): \[ \Delta t = \frac{\Delta p}{F} \] Substitute the values:
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