2. The azimuths of the back and forward tangents of a simple curve are N. 120 35' E. and S. 650 55' E. respectively . A line with bearing S 690 22' W intersects the forward tangent at a point 28.086 meters from the PT of the simple curve and the simple curve at point Z. If the long chord of the simple curve is 120.147 meters and stationing of V is at station 50 + 134, what would be the stationing of point Z and PT? Determine the numerical value of the unknown elements of the simple curve. Use arc definition.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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2. The azimuths of the back and forward
tangents of a simple curve are N. 120 35' E.
and S. 650 55' E. respectively . A line with
bearing S 690 22' W intersects the forward
tangent at a point 28.086 meters from the PT
of the simple curve and the simple curve at
point Z. If the long chord of the simple curve
is 120.147 meters and stationing of V is at
station 50 + 134, what would be the
stationing of point Z and PT? Determine the
numerical value of the unknown elements of
the simple curve. Use arc definition.
Transcribed Image Text:2. The azimuths of the back and forward tangents of a simple curve are N. 120 35' E. and S. 650 55' E. respectively . A line with bearing S 690 22' W intersects the forward tangent at a point 28.086 meters from the PT of the simple curve and the simple curve at point Z. If the long chord of the simple curve is 120.147 meters and stationing of V is at station 50 + 134, what would be the stationing of point Z and PT? Determine the numerical value of the unknown elements of the simple curve. Use arc definition.
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