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- What is the best approximation of the standard deviation ofthe measures -4, -3.0, 8, and 9?What if a professor returned an assignment to you and your assignment score is 85 had a standard deviation of 8 and the professor told you that the class mean was 75. What would be your percentile.Jack's clothing sells on average, 25 shirts per week, sometimes a little more, sometimes a little less but typically a deviation of about 3. The cost per jacket is $65. Because Jack's is located in a sketchy part of town their insurance on inventory is 33% on all goods. The good news is free shipping to customers although UPS charges Jack's $8.50 for every delivery. It takes 2 weeks from the time jackets are ordered until they are received. Jack's supplier has said they only ship by pallet, and each pallet contains 75 jackets. If the reorder point is 50 what is the average flow time?
- Alice was told that her reading test score was one standard deviation below to me if test scores were approximately normal with m= 86 and standard deviation= 4. What was Alice's score?The average resting heart rate for a normal adult is around 80 beats per minutes. A randomly selected group of 16 people who live in SF was taken and it was found that their average resting heart rate is 71.3 beats per minute. Assume that the standard deviation of the resting heart rate for any normal adult is 18 beats per minute. Test the claim that the average resting heart rate for people who live in SF is less than 80 beats per minute. Round your answer to the nearest tenth of a BPM For credit, the hypothesis test must contain: 1) Claim in terms of the appropriate parameter (e.g. μ = 4.5 m i l e s) 2) Null and alternative hypothesis 3) Sample evidence used 4) Test stat (z or t) , p-value and direction of test. (right, left or two tailed) 5) Whether you rejected or failed to reject the null hypothesis. 6) Conclusion telling us what the test concluded about your original claim.Help me solve pls
- The chart to the right shows that a professor's grading distribution is bell shaped, or normally shaped. The mean of the distribution is 74 and the standard deviation is 9. Using a Continuous Variable Normal Bell Distribution Model, calculate the minimum test score needed to score in the top 5% of the class. Complete your work in the worksheet by listing the formula inputs, labels for the formula inputs and make your calculations with formulas. This test problem is similar to what you studied in video # 32, 33 and 34 and homework problems # 17, 21 and 23. Relative Frequency Frequency Professor looks at all test score for a particular test (this is population data), and observes: 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0 Mean = 74 Median = 74 Mode = 73 SD=9 0 0 0 up to 10 up 10 to 20 0 20 up to 30 0 30 up to 40 2 40 up to 50 29 50 up to 60 X = Score 112 60 up to 70 225 70 up to 80 111 80 up to 90 21 2 90 up 100 up to 100 to 110You get hired as a server at a local restaurant, and the manage tells you that servers tips are $42 on average but vary about $12 (mean =42, standard deviation =12). You decide to track your tips to see if you make a different amount, but because this is your first job as a server, you don't know if you will make more or less in tips. After working 16 shifts, you find that your average mightly amount is $44.50 from tips test for a difference between this value and the population mean at the a=0.05 level of significance.Let's say that the mean score on this exam turns out to be 73 with a standard deviation of 12 and is normally distributed. If I gave a B to everyone who had an 80 or above, what percent of the class would get B's (or better)?
- According to the New York Daily News, March 5, 2014, people 65 years and older watch an average of 50.5 hours of TV per week. We will estimate the standard deviation to be 12.7 hours per week. Your town has many social programs for senior citizens which may reduce the amount of TV that older people watch. You want to find out if it is true that people 65 and older in your town watch less than 50.5 hours of TV per week. So, you sample 40 people 65 and older in your town. You find that the average time that the 40 people watch per week is 45.8 hours. Can the claim be supported to a level of significance of α = .02, test the hypothesis?The distribution of scores for an exam follow the rule of thumb for standard deviation. If the average score on the exam is 75 and the standard deviation is 5, what percentage of students would you expect to score between 65 and 85 on the exam (to 2 significant digits)?Please type