2. Suppose you are testing Но: р — 0.8 H1: p < 0.8, versus where n = 25. From your data, you calculate your test statistic value as +1.2. (a) Should you use z or t when finding a p-value for this scenario? (b) Calculate the p-value for this scenario. (c) Using a significance level of 0.062, what decision should you make (Reject Ho or Do Not Reject Ho)?
Q: 6. Suppose you are testing Ho: p= 0.8 H1 : p < 0.8, versus where n = 25. From your data, you…
A: Given n = 25 z = 1.2
Q: 6. Suppose you are testing Ho: p = 0.64 versus H₁: p < 0.64 where n = 25. From your data, you…
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- You wish to test the following claim (Ha) at a significance level of a = 0.001. H,:P = P2 Ha:pi > p You obtain 303 successes in a sample of size n = 488 from the first population. You obtain 159 successes in a sample of size ry = 266 from the second population. What is the test statistic for this sample? test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O There is not sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O The sample data support the claim that the first population…A survey claims that 9 out of 10 doctors recommend brand Wfor their patients who have children. To test this claim against the alternative that the actual proportion of doctors who recommend brand Wis less than 90%, a random sample of 100 doctors results in 85 who indicate that they recommend brand W. 1. What decision should you makeusing a significance level of 5%? 2. Summarize your conclusions in the context of the problem.You wish to test the following claim (H) at a significance level of a = 0.01. Ho: P₁ = P2 p1 H₁: P₁ P2 = 685 from You obtain 127 successes in a sample of size ni the first population. You obtain 131 successes in a sample of size n2 = 786 from the second population. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
- Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x= 99.11, y = 100.1, r=0.872, P-value = 0.000, and y = 7.99 +0.93x, where x represents the IQ score of the twin bom first. Find the best predicted value of y given that the twin born first has an IQ of 96? Use a significance level of 0.05. 1 Critical Values of the Pearson Correlation Coefficient r E Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is. Critical Values of the Pearson Correlation Coefficient r a = 0.01 NOTE: To test Ho: p=0 against H,: p#0, reject H, if the absolute value of r is greater than the critical value in the table. (Round to two decimal places as needed.) a = 0.05 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.834 0.798 0.765 0.735 0.708 8 0.707 9 0.666 10 0.632 11 0.602 0.576 0.553 12 0.684 13 0.661 0.641 0.623 0.606 14 0.532 0.514 15 16 17 0.497 0.482 0.468 0.456 0.444 0.590 0.575…You wish to test the following claim (HaHa) at a significance level of α=0.005. Ho:p=0.35 Ha:p≠0.35You obtain a sample of size n=650 in which there are 209 successful observations.Determine the test statistic formula for this test.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.35. There is not sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.35. The sample data support the claim that the population proportion is not equal to 0.35. There is not…You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly smaller than 68% at a significance level of αα = 0.05. According to your sample, 52 out of 82 potential voters prefer Candidate A. The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
- You are conducting a hypothesis test where the null hypothesis is that mu is less than or equal to 850. You are testing at the 0.01 significance level. You take a sample of size 64 and calculate your test statistic to be -1.50. What would your test statistic be if, rather than mu<= 850, your null hypothesis was that mu >= 850?20. Only about 10% of all people can wiggle their ears. Is this percent lower for millionaires? Of the 372 millionaires surveyed, 30 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is α Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly lower than 10% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of millionaires who can wiggle their ears is equal to 10%. The data suggest the populaton proportion is significantly lower than 10% at αα = 0.05, so there is statistically significant…You wish to test the following daim (Ha) at a significance level of a = 0.10. H,:P1 P2 You obtain 615 successes in a sample of size n1 = 704 from the first population. You obtain 490 successes in a sample of size n2 = 581 from the second population. critical value = [three decimal accuracy] test statistic = [three decimal accuracy] The test statistic is... O in the critical region O not in the critical region This test statistic leads to a decision to... O reject the null accept the null fail to reject the null As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is greater than the second population proportion. O There is not sufficient evidence to support that the first population proportion is greater than the second population proportion.
- You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.15. You use a significance level of a = 0.01. Но:р — 0.15 H1:p > 0.15 You obtain a sample of size n 137 in which there are 28 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is.. less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that. O There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. O There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. The sample data support…44You are conducting a hypothesis test where alternative (research) hypothesis is that mu is greater than 850. You are testing at the 0.01 significance level. You take a sample of size 64 and calculate your test statistic to be -1.50. What would your test statistic be if you were testing, instead, at the 0.10 significance level?