2. Suppose this is a random sample. Test the hypothesis that there is an association between mother's and respondent's education in the population, Use a = 0.05.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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I only need question 2 answered. Question 1’s are only there for reference.
Use the data below to answer questions #1-4.
Person id
Mother's
Respondent's
education
(X- Mean) * (Y
-Мean)
2.9 * 2.6 = 7.54
X- Mean
Y- Mean
(X-
Mean)?
(Y-
Mean)?
2#
education
1
16
16
16 - 13.1 = 2.9
16 - 13.4 = 2.6
2.92 = 8.41
2.62 = 6.76
2
16
18
16 - 13.1 = 2.9
18 - 13.4 = 4.6
2.9 * 4.6 = 13.34
2.92 = 8.41
4.62 = 21.16
3
12
14
(-1.1) * 0.6 = -0.66
(-1.1) * 0.6 = -0.66
(-4.1) * (-4.4) = 18.04
(-5.1) * (-5.6) = 28.56
5.9 * (-1.4) = -8.26
0.9 * 6.6 = 5.94
(-0.1) * (-0.4) = 0.04
(-1.1) * (-1.4) = 1.54
12 - 13.1 = -1.1
14 - 13.4 = 0.6
(-1.1)? = 1.21
(-1.1)? = 1.21
(-4.1)2 = 16.81
0.62 = 0.36
4
12
14
12 -13.1 = -1.1
14 - 13.4 = 0.6
0.62 = 0.36
(-4.4)2 = 19.36
(-5.1)2 = 26.01 (-5.6)² = 31.36
(-1.4)2 = 1.96
6.62 = 43.56
(-0.4)2 = 0.16
(-1.4)² = 1.96
5
9
9-13.1 = -4.1
9- 13.4 = -4.4
8.
8.
8- 13.1 = -5.1
8- 13.4 = -5.6
7
19
12
19 - 13.1 = 5.9
12 - 13.4 = -1.4
5.92 = 34.81
8
14
20
14 - 13.1 = 0.9
0.92 = 0.81
(-0.1)2 = 0.01
(-1.1)² = 1.21
20 - 13.4 = 6.6
13
11
13 - 13.1 = -0.1
13 - 13.4 = -0.4
10
12
12
12 - 13.1 = -1.1
12-13.4 = -1.4
13.1
13.4
6.542
9.89
12.7
1. Calculate Pearson's r. Write one or two sentences describing the results (Is there an
association? Is it positive or negative? Is it weak, moderate or strong?)
E(X
X)(Y – Y)
|
V[E(X - X)²][2(Y – Y)*]
6.542
r =
V9.89 x 12.7
0.584
There is a moderate positive association between how many years of education the respondents
had when compared to their mothers. Those with well-educated mothers are likely to be well-
educated themselves.
2. Suppose this is a random sample. Test the hypothesis that there is an association
between mother's and respondent's education in the population. Use a = 0.05.
Transcribed Image Text:Use the data below to answer questions #1-4. Person id Mother's Respondent's education (X- Mean) * (Y -Мean) 2.9 * 2.6 = 7.54 X- Mean Y- Mean (X- Mean)? (Y- Mean)? 2# education 1 16 16 16 - 13.1 = 2.9 16 - 13.4 = 2.6 2.92 = 8.41 2.62 = 6.76 2 16 18 16 - 13.1 = 2.9 18 - 13.4 = 4.6 2.9 * 4.6 = 13.34 2.92 = 8.41 4.62 = 21.16 3 12 14 (-1.1) * 0.6 = -0.66 (-1.1) * 0.6 = -0.66 (-4.1) * (-4.4) = 18.04 (-5.1) * (-5.6) = 28.56 5.9 * (-1.4) = -8.26 0.9 * 6.6 = 5.94 (-0.1) * (-0.4) = 0.04 (-1.1) * (-1.4) = 1.54 12 - 13.1 = -1.1 14 - 13.4 = 0.6 (-1.1)? = 1.21 (-1.1)? = 1.21 (-4.1)2 = 16.81 0.62 = 0.36 4 12 14 12 -13.1 = -1.1 14 - 13.4 = 0.6 0.62 = 0.36 (-4.4)2 = 19.36 (-5.1)2 = 26.01 (-5.6)² = 31.36 (-1.4)2 = 1.96 6.62 = 43.56 (-0.4)2 = 0.16 (-1.4)² = 1.96 5 9 9-13.1 = -4.1 9- 13.4 = -4.4 8. 8. 8- 13.1 = -5.1 8- 13.4 = -5.6 7 19 12 19 - 13.1 = 5.9 12 - 13.4 = -1.4 5.92 = 34.81 8 14 20 14 - 13.1 = 0.9 0.92 = 0.81 (-0.1)2 = 0.01 (-1.1)² = 1.21 20 - 13.4 = 6.6 13 11 13 - 13.1 = -0.1 13 - 13.4 = -0.4 10 12 12 12 - 13.1 = -1.1 12-13.4 = -1.4 13.1 13.4 6.542 9.89 12.7 1. Calculate Pearson's r. Write one or two sentences describing the results (Is there an association? Is it positive or negative? Is it weak, moderate or strong?) E(X X)(Y – Y) | V[E(X - X)²][2(Y – Y)*] 6.542 r = V9.89 x 12.7 0.584 There is a moderate positive association between how many years of education the respondents had when compared to their mothers. Those with well-educated mothers are likely to be well- educated themselves. 2. Suppose this is a random sample. Test the hypothesis that there is an association between mother's and respondent's education in the population. Use a = 0.05.
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