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2. Suppose that F is an antiderivative of function f, if f is continuous on [a, b], then So f(x)dx= ·( ) (A) F(a)-F(b) = (B) F(b)-F(a) (C) F(x) + C (D) F(x)

2. Suppose that F is an antiderivative of function f, if f is continuous on [a, b], then So f(x)dx= ·( ) (A) F(a)-F(b) = (B) F(b)-F(a) (C) F(x) + C (D) F(x)

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.CR: Chapter 3 Review
Problem 12CR: Determine whether each of the following statements is true or false and explain why. The derivative...
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Single choice questions. Answer question 2..

Single Choice Question 1. ſ f(x)dx+ſº f(x)dx= (A) ſº f(x)dx (B) f(x) dx (C) f f(x) dx (D) fd f(x)dx 2. Suppose that F is an antiderivative of function f, if ƒ is continuous on [a, b], then S f(x) dx = () (A) F(a)-F(b) (B) F(b)-F(a) (C) F(x) + C (D) F(x) 3. The area between the curves y = f(x) and y = g(x) and between x = a and = b is.. ·() (A) A = S₂ \g(x)— f(x)\dx (B) A= ſ₂ |ƒ(x)—g(x)\dx (D) A=f|f(x)— f(x)|dx (C) A= ſő |ƒ(x), g(x)|dx 4. If g' is continuous on [a, b] and ƒ is continuous on the range of u = g(x), then S₂ f(g(x))g'(x)dx=. ·() •g(b) (A) ff(u)du (B) ·( ) g(u)du g(a) g(a) (C) f f(u)du (D) fg(u)du 5. Suppose ƒ is continuous on [—a, a]. If ƒ is odd, then ſª f(x)dx=········( _ ) (A) 2 fő f(x)dx (B) 0 (C) 2 f f(x)dx (D) ff(x)dx
Transcribed Image Text:Single Choice Question 1. ſ f(x)dx+ſº f(x)dx= (A) ſº f(x)dx (B) f(x) dx (C) f f(x) dx (D) fd f(x)dx 2. Suppose that F is an antiderivative of function f, if ƒ is continuous on [a, b], then S f(x) dx = () (A) F(a)-F(b) (B) F(b)-F(a) (C) F(x) + C (D) F(x) 3. The area between the curves y = f(x) and y = g(x) and between x = a and = b is.. ·() (A) A = S₂ \g(x)— f(x)\dx (B) A= ſ₂ |ƒ(x)—g(x)\dx (D) A=f|f(x)— f(x)|dx (C) A= ſő |ƒ(x), g(x)|dx 4. If g' is continuous on [a, b] and ƒ is continuous on the range of u = g(x), then S₂ f(g(x))g'(x)dx=. ·() •g(b) (A) ff(u)du (B) ·( ) g(u)du g(a) g(a) (C) f f(u)du (D) fg(u)du 5. Suppose ƒ is continuous on [—a, a]. If ƒ is odd, then ſª f(x)dx=········( _ ) (A) 2 fő f(x)dx (B) 0 (C) 2 f f(x)dx (D) ff(x)dx
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