**Vapor-Liquid Equilibrium Problem Analysis**Substance A, a pure substance, is known to be in vapor-liquid equilibrium at a temperature of 50°C and a pressure of 0.08 bar. The following companies claim to also find Substance A in vapor-liquid equilibrium under different conditions:- **Company 1:** - Temperature: 323 K - Pressure: 0.1 bar- **Company 2:** - Temperature: 60°C - Pressure: 0.01 bar- **Company 3:** - Temperature: 60°C - Pressure: 0.08 bar**Question:**Which company or companies' claims must be false, and why?**Explanation:**To determine the validity of each company's claim, we compare their stated conditions to the known equilibrium state of Substance A (50°C, 0.08 bar). - **Company 1** reports conditions in Kelvin. We convert 323 K to Celsius: 323 K - 273.15 = 49.85°C. At 49.85°C, a pressure of 0.1 bar is reasonably close to the provided data, but not an exact match, indicating possible inaccuracy. - **Company 2** claims 60°C and 0.01 bar. The temperature is higher than 50°C, but the pressure is significantly lower, making this an unlikely state for vapor-liquid equilibrium.- **Company 3** states 60°C and 0.08 bar, slightly higher in temperature than the known equilibrium, but matching the pressure, suggesting a plausible state close to equilibrium.**Conclusion:**Company 2's claim is most likely false, as the pressure of 0.01 bar at 60°C is much lower than expected for similar equilibrium conditions, given the known data at 50°C and 0.08 bar.

Answered: Image /qna-images/answer/ec86f313-0141-4cb1-9f11-732c97a6daeb.jpg

2. Substance A (a pure substance) is known to be in vapor-liquid equilibrium at T = 50 °C and p = 0.08 bar. The following companies claim to also find substance A in vapor-liquid equilibrium at: Company 1: p = 0.1 bar Company 2: p = 0.01 bar Company 3 p = 0.08 bar Which company or companies claims must be false and why. T = 323 K T = 60 °C T = 60 °C

2. Substance A (a pure substance) is known to be in vapor-liquid equilibrium at T = 50 °C and p = 0.08 bar. The following companies claim to also find substance A in vapor-liquid equilibrium at: Company 1: p = 0.1 bar Company 2: p = 0.01 bar Company 3 p = 0.08 bar Which company or companies claims must be false and why. T = 323 K T = 60 °C T = 60 °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Give a clear explanation handwritten answer...give detailed answer.
At high temperature, HCl and O2 react to give Cl2 gas: 4HClg) + O2(g) ⇌ 2 Cl2 (g) + 2H2O(g) If HCl at 2.30 bar and O2 at 1.00 bar react at 750K, the equilibrium pressure of Cl2 is measured to be 0.93 bar. Determine the value of Keq at 750 K. Use a systematic approach to include setting up an ICE table, constructing equilibrium constant expression and show calculation involved.
1. A certain amount of NH4Cl(s) was put into a vacuum container, and then it is heated until equilibrium was reached: NH4Cl(s) == NH3(g) + HCl (g). Please write the number of phase p, the number of component C and the number of freedom F.
2
Please answer it correctly
Liquid and solid carbon dioxide (CO2) are in equilibrium at T = -50°C and p = 70 atm. The molar volume of liquid CO2 is 40 mL/mol and the molar volume of solid CO2 is 28 mL/mol at this temperature. What would happen if pressure in the system would increase by 10 atm at this temperature?
I need hand written solution only
NOBr(g) at 1 bar pressure is introduced into a evacuated chamber according to the equilibrium equation give below, it dissociates; 2NOBr(g) <=> 2NO(g) + Br2(g) at 25 degrees Celsius equilibrium is reached, the partial pressure is 0.60 bar of the NOBr. At 25 degrees Celsius what is the equilibrium constant for this reaction. Chose the most correct answer. a) 0.012 b) 0.062 c) 0.089 d)1.34
From the following vapor pressure data for ethyl amine, an estimate of the molar heat of vaporization of C₂H5NH₂ is | kJ/mol. P, mm Hg T, K 40.0 233 100. 248
▼ standard conditions Express your answer in kilojoules. AGixn = Submit Part B AGrxn= at equilibrium Express your answer in kilojoules. Submit Part C Π| ΑΣΦ AGrxn= Request Answer Submit IVE ΑΣΦ PICI = 2.58 atm ; P1₂ = 0.324 atm; Pcl₂ = 0.216 atm. Express your answer using one significant figure. Request Answer 17| ΑΣΦ Request Answer ? ? ? kJ kJ kJ
A sample of graphite sealed under 0.458 atm of CO2(g) at 1080 K forms CO(g) and makes Ptot = 0.757 atm at eq≡m. Find KP: C(s) + CO2(g) 2 CO(g) KP = Peq(CO)2 Set up an ICE Table: Use other geven data to calculate the unknown: Ptot = 0.757 atm = Peq(CO2) + Peq(CO)= 0.458 – x + 2x = 0.458+x x=o.299 atm Peq(CO2) = 0.458 – x = ______ atm Peq(CO) = 2x = ______ atm Kp=Peq(CO)2 / Peq(CO2) = _____^2 atm2/ _____ atm = ______ atm