2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3 P4 (s) ---> 3 P4O10 (s) + 10 KCI (s) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4O10? (B) How much reactant (P4) will be needed to produce 105. g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 1 mole of P4 = 123.88 grams of P4 1 mole of P4O10 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4010
2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3 P4 (s) ---> 3 P4O10 (s) + 10 KCI (s) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4O10? (B) How much reactant (P4) will be needed to produce 105. g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 1 mole of P4 = 123.88 grams of P4 1 mole of P4O10 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4010
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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