2. Solve the task 5.22 from the textbook. According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the sphere depicted in Fig. P5.22, Mo = 0 seeonde interad V sphere 4 FIGURE P5.22

Elements Of Electromagnetics
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Mo = 0 second
me.
inturad
2. Solve the task 5.22 from the textbook.
According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the
submerged portion of the object. For the sphere depicted in Fig. P5.22,
V=4 pr3 sphere
FIGURE P5.22
use bisection to determine the height, h, of the portion that is above water. Employ the following values
for your computation: r = 1 m, ps = density of sphere = 200 kg/m³, and pw = density of water =
1,000 kg/m³. Note that the volume of the above-water portion of the sphere can be computed with
nh2
V =
(3r – h)
3
Submission
You will submit the source code (the .m file) and the screenshot that shows the result.
Transcribed Image Text:Mo = 0 second me. inturad 2. Solve the task 5.22 from the textbook. According to Archimedes' principle, the buoyancy force is equal to the weight of fluid displaced by the submerged portion of the object. For the sphere depicted in Fig. P5.22, V=4 pr3 sphere FIGURE P5.22 use bisection to determine the height, h, of the portion that is above water. Employ the following values for your computation: r = 1 m, ps = density of sphere = 200 kg/m³, and pw = density of water = 1,000 kg/m³. Note that the volume of the above-water portion of the sphere can be computed with nh2 V = (3r – h) 3 Submission You will submit the source code (the .m file) and the screenshot that shows the result.
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