2. Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel) X6 fi(x) = 0.5x1 + X2 + 0.5x3 X7 2 = 0 X7 f2(x) = x3 + X4 + 2xs - f3(x) = x1 + X2 + x5 X7 -- 3D f.(x) = -28837x1 – 139009x2 – 78213x3 + 18927x4 + 8427x5 13492 X6 - 10690- X7 = 0 fs(x) = x1 + xz + X3 + X4 + Xs - 1 = 0 fo(x) = 400x,x² – 1.7837×10$x,X5 = 0 f;(x) = x,X3 – 2.6058x4 = 0 %3D %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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2. Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel)
X6
f.(x) = 0.5x1 + x2 + 0.5x3
= 0
--
%3D
X7
2
f2(x) = x3 + X4 + 2x5
-- -
X7
1
f3(x) = x1 + X2 + x5 -
- =
f.(x) = -28837x1 – 139009x2 – 78213x3 + 18927x4 + 8427x5
%3D
13492
10690*é = 0
fs(x) = x1 + x2 + X3 + X4 + X5 – 1 = 0
fo(x) = 400x,x? – 1.7837×10$x3X5 = 0
f,(x) = x1X3 – 2.6058x4 = 0
%3D
Transcribed Image Text:2. Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel) X6 f.(x) = 0.5x1 + x2 + 0.5x3 = 0 -- %3D X7 2 f2(x) = x3 + X4 + 2x5 -- - X7 1 f3(x) = x1 + X2 + x5 - - = f.(x) = -28837x1 – 139009x2 – 78213x3 + 18927x4 + 8427x5 %3D 13492 10690*é = 0 fs(x) = x1 + x2 + X3 + X4 + X5 – 1 = 0 fo(x) = 400x,x? – 1.7837×10$x3X5 = 0 f,(x) = x1X3 – 2.6058x4 = 0 %3D
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