2. Solve (D3 + 4D² + 5D + 2)F) = 0. 3. Solve (D3 + 2D² – D – 2)(f) = 0. 4. Consider the general solution of number 3. Find a solution u(x) that will satisfy the following initial condition: µ(0) = 1 Dμ (0 )2 D²µ(0) = –1

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