2. Show that, on the space of continuous functions C[0, 1] the distances defined by the norms =√₁|f(t)\Pdt, ‚ = max |ƒ(x)\, ||f||1₁ = [₁ |ƒ(t)|dt, ||f||2= ||f||∞ = are mutually non-equivalent.
2. Show that, on the space of continuous functions C[0, 1] the distances defined by the norms =√₁|f(t)\Pdt, ‚ = max |ƒ(x)\, ||f||1₁ = [₁ |ƒ(t)|dt, ||f||2= ||f||∞ = are mutually non-equivalent.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![2. Show that, on the space of continuous functions C[0, 1] the distances
defined by the norms
= max| |ƒ(x)\, ||f||₁ = √| | \ƒ(1)|dt, ||f||2 = √√√²\ƒ(1)|²³dt,
||f|| = max
are mutually non-equivalent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb593f6c0-a50f-44ba-ba62-b97c71d29967%2Ff754c1e0-87de-4a64-b519-3ff8187e11c2%2Fp44txt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Show that, on the space of continuous functions C[0, 1] the distances
defined by the norms
= max| |ƒ(x)\, ||f||₁ = √| | \ƒ(1)|dt, ||f||2 = √√√²\ƒ(1)|²³dt,
||f|| = max
are mutually non-equivalent.
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