2. (Separable and Newton's Law of Cooling) Let T(t) be the temperature of the room and T, the outside temperature (assumed to be constant in Newton's law). Then by Newton's law k(T - T,). In this problem, the rate at which a substance cools in air is directly proportional to the difference between the temperatures of the substance and that of air. The temperature of air, TA, is 30° and the substance cools from 100' to 70' in 15 minutes. How long does it take for the substance to cool from 100' to 50'? A. 45.30 minutes B. 43.60 minutes C. 35.39 minutes D. 33.59 minutes

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Question
2. (Separable and Newton's Law of Cooling) Let T(t) be the temperature of the room and T, the
outside temperature (assumed to be constant in Newton's law). Then by Newton's law
dt
k(T – T,). In this problem, the rate at which a substance cools in air is directly proportional to
the difference between the temperatures of the substance and that of air. The temperature of
air, TA, is 30° and the substance cools from 100° to 70° in 15 minutes. How long does it take for
the substance to cool from 100 to 50"?
A. 45.30 minutes
B. 43.60 minutes
C. 35.39 minutes
D. 33.59 minutes
Solution. Hints:
1. Find the general solution of the equation = k(T – T,) by separable.
2. Let t = 0 and T = 100° to find C.
3. Let t = 15 and T = 70 to find k.
4. Let T = 50° to find t.
Transcribed Image Text:2. (Separable and Newton's Law of Cooling) Let T(t) be the temperature of the room and T, the outside temperature (assumed to be constant in Newton's law). Then by Newton's law dt k(T – T,). In this problem, the rate at which a substance cools in air is directly proportional to the difference between the temperatures of the substance and that of air. The temperature of air, TA, is 30° and the substance cools from 100° to 70° in 15 minutes. How long does it take for the substance to cool from 100 to 50"? A. 45.30 minutes B. 43.60 minutes C. 35.39 minutes D. 33.59 minutes Solution. Hints: 1. Find the general solution of the equation = k(T – T,) by separable. 2. Let t = 0 and T = 100° to find C. 3. Let t = 15 and T = 70 to find k. 4. Let T = 50° to find t.
Expert Solution
steps

Step by step

Solved in 5 steps

Blurred answer
Knowledge Booster
Differential Equation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,