2. Refer to figure 1.B. The capacitor in initially uncharged. The switch S is elosed at t=0. Since the capacitor at t= o+ behaves like a conducting wirelwith zero resistance] and at t oo like an open circuit with infinite resistance]: (a) The effective resistance of the circuit at t=0t in: 4+ - 5.6n (True, False) (b) After a very long time (t - 0) the effective resistance of the circuit in: 4+2 = 6n (True, False) (e) At t-ot the voltagen acrosn the 8n resintor and 20 resistor are the same. (True, Palae) (d) At = ot the voltage across 4n , 80 and 20 renistors are 4.3V , 1.7V and 1.7V respectively. (e) At t- oo the voltagen across the 8n resistor in zero because the capacitor in fully charged and letu no current pasa through it behaves (True, Fatse) like an open circuit). (True, Falae) (1) At t- o the current is (True, False) (g) At t- 0o the voltage across the 20 is 2V. (True, False) (h) At t-oo the voltage across the 1F capacitor is 2V. (True, False)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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letter questions d,e,f,g,h  the previous questions were already answered 

### Circuit Diagram (B) Explanation

This image depicts an electrical circuit with the following components:

1. **Battery**: 
   - Voltage: 6V
   - Positioned in the bottom left corner of the circuit.

2. **Resistors**: 
   - There are three resistors present in the circuit.
     - A 4 Ω resistor is connected in series with the battery.
     - An 8 Ω resistor is positioned vertically in the middle of the circuit.
     - A 2 Ω resistor is on the right side of the circuit, connected in parallel with the 8 Ω resistor.

3. **Capacitor**:
   - Capacitance: 1 F
   - Placed in parallel with the 8 Ω resistor, above it in the circuit diagram.

4. **Switch (S)**:
   - Located at the top left, just after the battery, controlling the flow of current in the circuit.

### Circuit Explanation
- **Series and Parallel Configuration**: 
  - The circuit includes both series and parallel configurations. The initial segment with the 6V battery and 4 Ω resistor is in series. The 8 Ω resistor and the 1 F capacitor are parallel to the other part of the circuit which includes the 2 Ω resistor.
  
- **Functionality**: The switch (S) can be toggled to open or close the circuit, controlling the current flow. When the switch is closed, current flows, charging the capacitor while distributing voltage across the resistors.
  
This circuit illustrates a basic mixed series-parallel configuration often used in educational contexts to explain fundamental electrical concepts, including the behavior of capacitors and resistors in different setups.
Transcribed Image Text:### Circuit Diagram (B) Explanation This image depicts an electrical circuit with the following components: 1. **Battery**: - Voltage: 6V - Positioned in the bottom left corner of the circuit. 2. **Resistors**: - There are three resistors present in the circuit. - A 4 Ω resistor is connected in series with the battery. - An 8 Ω resistor is positioned vertically in the middle of the circuit. - A 2 Ω resistor is on the right side of the circuit, connected in parallel with the 8 Ω resistor. 3. **Capacitor**: - Capacitance: 1 F - Placed in parallel with the 8 Ω resistor, above it in the circuit diagram. 4. **Switch (S)**: - Located at the top left, just after the battery, controlling the flow of current in the circuit. ### Circuit Explanation - **Series and Parallel Configuration**: - The circuit includes both series and parallel configurations. The initial segment with the 6V battery and 4 Ω resistor is in series. The 8 Ω resistor and the 1 F capacitor are parallel to the other part of the circuit which includes the 2 Ω resistor. - **Functionality**: The switch (S) can be toggled to open or close the circuit, controlling the current flow. When the switch is closed, current flows, charging the capacitor while distributing voltage across the resistors. This circuit illustrates a basic mixed series-parallel configuration often used in educational contexts to explain fundamental electrical concepts, including the behavior of capacitors and resistors in different setups.
Certainly! Here is a transcription of the provided image, suitable for an educational website:

---

2. Refer to figure 1B. The capacitor is initially uncharged. The switch S is closed at \( t = 0 \).

Since the capacitor at \( t = 0^+ \) behaves like a conducting wire (with zero resistance) and at \( t = \infty \) like an open circuit (with infinite resistance):

(a) The effective resistance of the circuit at \( t = 0^+ \) is: 

\[
4 + \left(\frac{24 \cdot 8}{24 + 8}\right) = 5.6 \Omega
\]

(True, False)

(b) After a very long time (\( t \rightarrow \infty \)) the effective resistance of the circuit is: \( 4 + 2 = 6\Omega \) 

(True, False)

(c) At \( t = 0^+ \) the voltages across the 8Ω resistor and 2Ω resistor are the same. 

(True, False)

(d) At \( t = 0^+ \) the voltage across 4Ω, 8Ω, and 2Ω resistors are 4.3V, 1.7V, and 1.7V respectively. 

(True, False)

(e) At \( t \rightarrow \infty \) the voltages across the 8Ω resistor is zero because the capacitor is fully charged and lets no current pass through it (behaves like an open circuit). 

(True, False)

(f) At \( t \rightarrow \infty \) the current is 

\[
\frac{6}{(2+4+1)} = 1A
\] 

(True, False)

(g) At \( t \rightarrow \infty \) the voltage across the 2Ω is 2V. 

(True, False)

(h) At \( t \rightarrow \infty \) the voltage across the 1F capacitor is 2V. 

(True, False)

---

### Explanation of Diagram

The problem refers to a circuit diagram which includes:

- A switch \( S \).
- A capacitor.
- Resistors of values 4Ω, 8Ω, and 2Ω.
  
The scenario discusses the behavior of the circuit both at the moment just after closing the switch (\( t = 0^
Transcribed Image Text:Certainly! Here is a transcription of the provided image, suitable for an educational website: --- 2. Refer to figure 1B. The capacitor is initially uncharged. The switch S is closed at \( t = 0 \). Since the capacitor at \( t = 0^+ \) behaves like a conducting wire (with zero resistance) and at \( t = \infty \) like an open circuit (with infinite resistance): (a) The effective resistance of the circuit at \( t = 0^+ \) is: \[ 4 + \left(\frac{24 \cdot 8}{24 + 8}\right) = 5.6 \Omega \] (True, False) (b) After a very long time (\( t \rightarrow \infty \)) the effective resistance of the circuit is: \( 4 + 2 = 6\Omega \) (True, False) (c) At \( t = 0^+ \) the voltages across the 8Ω resistor and 2Ω resistor are the same. (True, False) (d) At \( t = 0^+ \) the voltage across 4Ω, 8Ω, and 2Ω resistors are 4.3V, 1.7V, and 1.7V respectively. (True, False) (e) At \( t \rightarrow \infty \) the voltages across the 8Ω resistor is zero because the capacitor is fully charged and lets no current pass through it (behaves like an open circuit). (True, False) (f) At \( t \rightarrow \infty \) the current is \[ \frac{6}{(2+4+1)} = 1A \] (True, False) (g) At \( t \rightarrow \infty \) the voltage across the 2Ω is 2V. (True, False) (h) At \( t \rightarrow \infty \) the voltage across the 1F capacitor is 2V. (True, False) --- ### Explanation of Diagram The problem refers to a circuit diagram which includes: - A switch \( S \). - A capacitor. - Resistors of values 4Ω, 8Ω, and 2Ω. The scenario discusses the behavior of the circuit both at the moment just after closing the switch (\( t = 0^
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