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2. P(X = x) =55 x², if x € {1,2,3,4and 5} %3D 0,otherwise 3. P(X = x) = if x € {1,2,3,4,5,6} 0,otherwise if x € {1,2,3, 4,5, 6) 0, otherwise 4. P(X = x) =91

2. P(X = x) =55 x², if x € {1,2,3,4and 5} %3D 0,otherwise 3. P(X = x) = if x € {1,2,3,4,5,6} 0,otherwise if x € {1,2,3, 4,5, 6) 0, otherwise 4. P(X = x) =91

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Note: Number 1 is already answered which is on the right picture. On the right picture should be the format for your answer in number 2, 3, and 4.
WEEK 2 Show that each of the Allowing is o probobility mass Runchon 4) P(X-x) =3X, f xE (L2) 0, otherwise By Subshhuhion P(X= 4)= P(X = 2) Therfove P(x) 30 Check the sum of Probalaliies +专 2. %3D 3. PMF
Transcribed Image Text:WEEK 2 Show that each of the Allowing is o probobility mass Runchon 4) P(X-x) =3X, f xE (L2) 0, otherwise By Subshhuhion P(X= 4)= P(X = 2) Therfove P(x) 30 Check the sum of Probalaliies +专 2. %3D 3. PMF
Weekly activity (WEEK2) Show that each of the following is a probability mass function. if x E (1,2} 1. P(X = x) = 0, otherwise =x2, if x E {1,2,3,4and 5} 0, otherwise 2. P(X = x) ={55 if x € {1,2,3, 4,5,6) 0, otherwise 3. P(X = x) = {6' if x € {1,2,3,4,5, 6} 4. P(X = x) = 91' 0, otherwise
Transcribed Image Text:Weekly activity (WEEK2) Show that each of the following is a probability mass function. if x E (1,2} 1. P(X = x) = 0, otherwise =x2, if x E {1,2,3,4and 5} 0, otherwise 2. P(X = x) ={55 if x € {1,2,3, 4,5,6) 0, otherwise 3. P(X = x) = {6' if x € {1,2,3,4,5, 6} 4. P(X = x) = 91' 0, otherwise
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