2. PURPOSE: To determine the specific heat of glass marbles 3. DATA: Mass - marbles (grams) 21.ll6gx 24 TC 105 T:C water - T; (°C) marbles - T; (°C) Time (minutes) Mixture Temperature (°C) 29.0°C 28.0°C 27.0°C 26.0°C 26.0°C 0.5 1.0 1.5 2.0 2.5 3.0 4. CALCULATIONS: a. Calculate the mass of water. 1o4/200.MI 1 0M b. Water Tf= Marbles Tr= %3D c. Calculate the ATmarbles and ATwater ATmarbles = T; - Tf = °C - °C = °C %3D ATwater = Tf - Tị °C - °C °C d. Calculate the heat gained by the water. q = mcAT e. Calculate the specific heat capacity of the marbles. q lost %3D 9 gained (mmarbles)(c)(ATmarbles) = 9gained by water
2. PURPOSE: To determine the specific heat of glass marbles 3. DATA: Mass - marbles (grams) 21.ll6gx 24 TC 105 T:C water - T; (°C) marbles - T; (°C) Time (minutes) Mixture Temperature (°C) 29.0°C 28.0°C 27.0°C 26.0°C 26.0°C 0.5 1.0 1.5 2.0 2.5 3.0 4. CALCULATIONS: a. Calculate the mass of water. 1o4/200.MI 1 0M b. Water Tf= Marbles Tr= %3D c. Calculate the ATmarbles and ATwater ATmarbles = T; - Tf = °C - °C = °C %3D ATwater = Tf - Tị °C - °C °C d. Calculate the heat gained by the water. q = mcAT e. Calculate the specific heat capacity of the marbles. q lost %3D 9 gained (mmarbles)(c)(ATmarbles) = 9gained by water
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Help me fill in the blanks on this paper and do the math part.
![**Lab Experiment: Determining Specific Heat**
**Name:** [Your name]
**Partner:** [Your partner's name]
---
**Purpose:**
To determine the specific heat of glass marbles.
---
**Data:**
| Mass - Marbles (grams) | 21.16 g |
|------------------------|-------------|
| Water - Ti (°C) | 24.7°C |
| Marbles - Ti (°C) | 105.1°C |
**Mixture Temperature (°C) Over Time:**
| Time (minutes) | Temperature (°C) |
|----------------|------------------|
| 0 | 29.0°C |
| 0.5 | 28.0°C |
| 1.0 | 27.0°C |
| 1.5 | 26.0°C |
| 2.0 | 26.0°C |
| 2.5 | 26.0°C |
| 3.0 | 26.0°C |
---
**Calculations:**
**a. Calculate the mass of water:**
\[ \frac{1.0 \text{g}}{1 \text{mL}} \times 200 \text{mL} = \]
**b. Water Tf = Marbles Tf:**
\[ 4.18 \]
**c. Calculate the ΔT for marbles and water:**
\[ \Delta T_{\text{marbles}} = Ti - Tf = \, ^\circ\text{C} - \, ^\circ\text{C} = \, ^\circ\text{C} \]
\[ \Delta T_{\text{water}} = Tf - Ti = \, ^\circ\text{C} - \, ^\circ\text{C} = \, ^\circ\text{C} \]
**d. Calculate the heat gained by the water:**
\[ q = mc\Delta T \]
**e. Calculate the specific heat capacity of the marbles:**
\[ q_{\text{lost}} = q_{\text{gained}} \]
\[ (m_{\text{marbles}})(c)(\Delta T_{\text{marbles}}) = q_{\text{gained by water}} \]
---
Ensure all calculations are completed and](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a62a850-db07-4b81-a9cb-d3a9f3b08dd2%2Fde6542c6-2343-417d-bef8-a3186a9c608b%2Fojaujsr.jpeg&w=3840&q=75)
Transcribed Image Text:**Lab Experiment: Determining Specific Heat**
**Name:** [Your name]
**Partner:** [Your partner's name]
---
**Purpose:**
To determine the specific heat of glass marbles.
---
**Data:**
| Mass - Marbles (grams) | 21.16 g |
|------------------------|-------------|
| Water - Ti (°C) | 24.7°C |
| Marbles - Ti (°C) | 105.1°C |
**Mixture Temperature (°C) Over Time:**
| Time (minutes) | Temperature (°C) |
|----------------|------------------|
| 0 | 29.0°C |
| 0.5 | 28.0°C |
| 1.0 | 27.0°C |
| 1.5 | 26.0°C |
| 2.0 | 26.0°C |
| 2.5 | 26.0°C |
| 3.0 | 26.0°C |
---
**Calculations:**
**a. Calculate the mass of water:**
\[ \frac{1.0 \text{g}}{1 \text{mL}} \times 200 \text{mL} = \]
**b. Water Tf = Marbles Tf:**
\[ 4.18 \]
**c. Calculate the ΔT for marbles and water:**
\[ \Delta T_{\text{marbles}} = Ti - Tf = \, ^\circ\text{C} - \, ^\circ\text{C} = \, ^\circ\text{C} \]
\[ \Delta T_{\text{water}} = Tf - Ti = \, ^\circ\text{C} - \, ^\circ\text{C} = \, ^\circ\text{C} \]
**d. Calculate the heat gained by the water:**
\[ q = mc\Delta T \]
**e. Calculate the specific heat capacity of the marbles:**
\[ q_{\text{lost}} = q_{\text{gained}} \]
\[ (m_{\text{marbles}})(c)(\Delta T_{\text{marbles}}) = q_{\text{gained by water}} \]
---
Ensure all calculations are completed and
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