2. Prove that d [(2x+1)³] (2x+1)³(4x-19) (x-3)² dx = Then, -5 (2x+1)(8x-38) 3(x-3)² dx.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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2.
Prove that
dx
(2x+1)}] (2x+1) (4x-19)
X-3
(x-3)²
=
Then,
-5 (2x+1)²(8x-38)
3(x-3)²
-dx.
Transcribed Image Text:2. Prove that dx (2x+1)}] (2x+1) (4x-19) X-3 (x-3)² = Then, -5 (2x+1)²(8x-38) 3(x-3)² -dx.
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