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2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 3.00 ppm P 4.00 ppm P Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. 0.205 0.410 0.615 0.820

2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 3.00 ppm P 4.00 ppm P Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. 0.205 0.410 0.615 0.820

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 ml. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 0.205 0.410 3.00 ppm P 0.615 4.00 ppm P 0.820 Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. (b) Calculate the phosphate concentration in the urine as millimoles per liter. (c) Calculate the ratio of HPO, to H,PO, in the sample: K= 1.1 x 10 K,= 7.5 x 10+ K,= 4.8 x 10-
Transcribed Image Text:2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 ml. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 0.205 0.410 3.00 ppm P 0.615 4.00 ppm P 0.820 Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. (b) Calculate the phosphate concentration in the urine as millimoles per liter. (c) Calculate the ratio of HPO, to H,PO, in the sample: K= 1.1 x 10 K,= 7.5 x 10+ K,= 4.8 x 10-
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