2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 mL. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 3.00 ppm P 4.00 ppm P Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. 0.205 0.410 0.615 0.820

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2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the
phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color.
This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A
1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and
was diluted to a volume of 50.0 ml. A series of phosphate standards was similarly treated. The
absorbance of the solutions at 690 nm, measured against a blank, were as follows:
Solution
Absorbance
1.00 ppm P
2.00 ppm P
0.205
0.410
3.00 ppm P
0.615
4.00 ppm P
0.820
Urine sample 0.625
(a) Calculate the number of grams of phosphorus excreted per day.
(b) Calculate the phosphate concentration in the urine as millimoles per liter.
(c) Calculate the ratio of HPO, to H,PO, in the sample:
K= 1.1 x 10
K,= 7.5 x 10+
K,= 4.8 x 10-
Transcribed Image Text:2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color. This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A 1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and was diluted to a volume of 50.0 ml. A series of phosphate standards was similarly treated. The absorbance of the solutions at 690 nm, measured against a blank, were as follows: Solution Absorbance 1.00 ppm P 2.00 ppm P 0.205 0.410 3.00 ppm P 0.615 4.00 ppm P 0.820 Urine sample 0.625 (a) Calculate the number of grams of phosphorus excreted per day. (b) Calculate the phosphate concentration in the urine as millimoles per liter. (c) Calculate the ratio of HPO, to H,PO, in the sample: K= 1.1 x 10 K,= 7.5 x 10+ K,= 4.8 x 10-
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