2. Perform the following calculations and report the answers with appropriate units and the correct number of significant figures: a. 53.18 g+ 1.014 g+ 0.3270 g 54.1999 b. 10.35 cm x 4.15 cm x 1.10 cm c. 36.140 g ÷ 4.08 mL (2 Q57643r4 l. ol4g = B4.5295 : 54.52195
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- Although the preferred SI unit of area is the square meter, land is often measured in the metric system in hectares (ha). One hectare is equal to 10,000 m2. In the English system, land is often measured in acres (1 acre = 160 rod2). Use the exact conversions and those given in Exercise 47 to calculate the following. a. 1 ha = __________ km2 b. The area of a 5.5-acre plot of land in hectares, square meters, and square kilometers c. A lot with dimensions 120 ft by 75 ft is to be sold for 6500. What is the price per acre? What is the price per hectare?What is the difference between reporting the quantity nine inches as 9 inches and 9.00 inches?III. Perform these calculations and express the result with the proper number of significant figures. a. (4.850 g – 2.34 g)/1.3 mL b. (4.66 x 10-3) × 4.666 c. 0.003400/65.2
- digits when measurements are multiplied o... Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. 7.81 x 0.6 mL =g ml. mol 846.32 mol + 0.29 L %3D L. mol x 15. L L. = |mol 78.1Bud N. Chemist must determine the density of a mineral sample. His five trials yield densities of 5.15 g/cm3, 4.83 g/cm3, 5.08 g/cm3, 4.97 g/cm3, 5.12 g/cm3. Independent studies found the correct density to be 5.06 g/cm3. Which of the following is incorrect? a. The mean of his analysis is 5.03 g/cm3 indicating an error of 0.03 g/cm3 from the correct density B.His data has a standard deviation of 0.017 g/cm3 C.His data has a relative standard deviation of 2.60% D. He can report his analyzed density as 5.0±0.2 g/cm3 at a 95% confidence level E. The true value (population mean) is found within the confidence interval of Bud’s work1. A student weighs an empty special round bottom flask and stopper. He finds the mass to be 56.972 g. He then adds about 5 mL of an unknown liquid and heats the flask in a boiling water bath at 100°C. He allows all the liquid to vaporized and then removes the flask from the bath, stoppers it, and lets it cool. Upon cooling, he briefly removes the stopper, then replaces it and weighs the flask and condensed vapor, obtaining a mass of 57.917 g. The volume of the flask is known to be 240.2 mL. The barometric pressure in the laboratory that day is 743 mm Hg. What was the pressure of the vapor in the flask in atm? O 0.9776 atm 0.98 atm 0.978 atm 0.977 atm
- 13. The mass of water delivered by a buret is 11.8159 g at 15 °C. What is the calculated actual volume based on significant figures? NOTE: You will report the actual volume deliver in Expt 1 to two decimal places since all class A 50 mL buret readings are to two decimal places. 11.827 11.792 11.805 11.8401. How many significant figures should be retained in the result of the following calculation? 12.00000 x 0.9893 / 13.00335 x 0.0107 a. 2 b. 3 с. 4 d. 5significant figures and units. 3. Perform the following calculations and report the answer with the correct number of A. (9.2030 g)(0.00230 g) + 0.1020 g² = 00²0211237 0.10205² 0.123292 B. 234.020 g- 184.08 g 382.402 mL-326.322 mL (1 fl oz = 29.6 mL) 4. An aluminum beverage can contains 12.0 fluid ounces of liquid. Express this volume in liters. 12. uffaz X 560 080ML 49.949 = 0.8905g/mL CHE 1011 29.6mL = 355.2 mL Ift:0² (1 in = 2.54 cm) 5. What is the volume, in cubic centimeters, of a brick that is 4.0 in x 2.7 in × 8.0 in? 4.0A x 2,54 cm = 10.16cm liAcc 207 + x 2.54cm = 60858cm هذا 8.0MAX 2.54cm ITA 20032cm So volume 20.32cm x 6.858cm x 200320 1415.84 cm³ 6. The S.I. unit of energy is the joule, J (1 J = 1 kgom²/s²). Another energy unit, the erg, was once in widespread use (1 erg = 1 gocm²/s²). Calculate the number of ergs in 1.0 J. Page 2 of 2
- 6. What is the mass, in g, of a piece of iron that has a volume of 1.50 x 10² and a density of 7.20 g/mL?Mass of cup + water Mass of empty cup Mass of water Initial water temperature Final water temperature Change in water temperature 103.4 g 1.6 g ? A 8400 Joules B 101.6 Joules C 3300 Joules D 7.80 Joules 19.8°C 27.6°C ? 15. For the laboratory data above, determine the amount of energy absorbed/lost by the water in joules. Round your answer to the correct number of significant figures. (Specific Heat of water= 4.18 J/g °C)1. All answers to be entered via short answer are in the numerical format and presented up to the 3rd decimal place. Add trailing zeros if necessary, to complete your answer. NO NEED TO INCLUDE THE UNIT. For uniformity of answers, please be guided by the following examples: If your answer is 5.627594, enter 5.628 If your answer is 3.129934, enter 3.130 If your answer is 8.38, enter 8.380 If your answer is 1.2, enter 1.200 If your answer is 25, enter 25.000 If your answer is less than the value of 1, always place a zero before the decimal point (example: 0.5, enter 0.500) 2. In cases for answers in the exponential format, please be guided by the following examples and format: Do not convert your answer to decimal format If your answer from the calculator is 1.23454566 x 10E-4, enter 1.235x10^-4 (no spaces in between) If your answer from the calculator is 7.379566 x 10E-5, enter 7.38x10^-5 (no spaces in between) 3. For the atomic weights, it should be rounded to the nearest whole…