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2. Now for a different ride design, you are now concerned with the passenger compartment coming to a safe stop. The passenger compartment is traveling with an initial velocity of 125 ft/sec. In an emergency, the brakes can be applied to lock all 4 wheels. When this happens, Coulomb friction with a force proportional to the coefficient of friction, u, times the normal force, brings the compartment to a complete stop. Use the acceleration due to gravity, g = 32.2 ft/sec². If the compartment is required to come to a complete stop in 8 seconds during an emergency, what is the required friction coefficient, µ? Used with permission from "Engineering Mechanics: Dynamics," McGill/King, 4th Ed., 2003 μ = 0.3 μ=2.06 μ = 0.485 None of the above

2. Now for a different ride design, you are now concerned with the passenger compartment coming to a safe stop. The passenger compartment is traveling with an initial velocity of 125 ft/sec. In an emergency, the brakes can be applied to lock all 4 wheels. When this happens, Coulomb friction with a force proportional to the coefficient of friction, u, times the normal force, brings the compartment to a complete stop. Use the acceleration due to gravity, g = 32.2 ft/sec². If the compartment is required to come to a complete stop in 8 seconds during an emergency, what is the required friction coefficient, µ? Used with permission from "Engineering Mechanics: Dynamics," McGill/King, 4th Ed., 2003 μ = 0.3 μ=2.06 μ = 0.485 None of the above

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2. Now for a different ride design, you are now concerned with the passenger compartment coming to a safe stop. The passenger compartment is traveling with an initial velocity of 125 ft/sec. In an emergency, the brakes can be applied to lock all 4 wheels. When this happens, Coulomb friction with a force proportional to the coefficient of friction, u, times the normal force, brings the compartment to a complete stop. Use the acceleration due to gravity, g = 32.2 ft/sec². If the compartment is required to come to a complete stop in 8 seconds during an emergency, what is the required friction coefficient, µ? Used with permission from "Engineering Mechanics: Dynamics," McGill/King, 4th Ed., 2003 μ = 0.3 μ=2.06 μ = 0.485 None of the above
Transcribed Image Text:2. Now for a different ride design, you are now concerned with the passenger compartment coming to a safe stop. The passenger compartment is traveling with an initial velocity of 125 ft/sec. In an emergency, the brakes can be applied to lock all 4 wheels. When this happens, Coulomb friction with a force proportional to the coefficient of friction, u, times the normal force, brings the compartment to a complete stop. Use the acceleration due to gravity, g = 32.2 ft/sec². If the compartment is required to come to a complete stop in 8 seconds during an emergency, what is the required friction coefficient, µ? Used with permission from "Engineering Mechanics: Dynamics," McGill/King, 4th Ed., 2003 μ = 0.3 μ=2.06 μ = 0.485 None of the above
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