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2. m/DCB= 105°, m/DAB = 4. m/ABC= 110°, m/ADC = . qasimout M 6. XY = 32, BC = 20, AD = B 82² X 82² 82² D C 106 Y A 2132)=x+20

2. m/DCB= 105°, m/DAB = 4. m/ABC= 110°, m/ADC = . qasimout M 6. XY = 32, BC = 20, AD = B 82² X 82² 82² D C 106 Y A 2132)=x+20

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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#2,#4,#6.. ABCD is an isosceles trapezoid with midsegment XY.
2. m/DCB= 105°, m/DAB = 4. m/ABC= 110°, m/ADC = ga 6. XY = 32, BC = 20, AD: X 82² 82² 82² D A 2(32) = x + 20 C 106 Y
Transcribed Image Text:2. m/DCB= 105°, m/DAB = 4. m/ABC= 110°, m/ADC = ga 6. XY = 32, BC = 20, AD: X 82² 82² 82² D A 2(32) = x + 20 C 106 Y
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