2. Let X = (a, b, c, d, e} and t = {(O, {a, c, d), (b, c, d, e), (a), (C, d), X) then subbase of (X, T) is OB - (0, X) OB = {{a.). (b), (c). (d), (e}} OB= {{a.), (a. c, d), (b, c, d. e})

Advanced Engineering Mathematics
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ISBN:9780470458365
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Chapter2: Second-order Linear Odes
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7. Let X = {a, b, c, d}, select any two most suitable option *
B={{1,2), (2, 4}} can not be a base for any topology
O One can not find sub base from basis
(0, X) be trivial basis
UB {{1), (2), (3). (4)) be subspace for discrete topology on X
%3D
Transcribed Image Text:7. Let X = {a, b, c, d}, select any two most suitable option * B={{1,2), (2, 4}} can not be a base for any topology O One can not find sub base from basis (0, X) be trivial basis UB {{1), (2), (3). (4)) be subspace for discrete topology on X %3D
2. Let X = {a, b, C, d, e} and t = {(0, {a, c, d), {b, c, d, e), (a), (C, d), X} then subbase of (X, T) is
O B = (0, X)
O B = {{a.). (b), {c), (d), (e}}
O B= {{a.), fa. c, d). [b, c, d, e}}
Transcribed Image Text:2. Let X = {a, b, C, d, e} and t = {(0, {a, c, d), {b, c, d, e), (a), (C, d), X} then subbase of (X, T) is O B = (0, X) O B = {{a.). (b), {c), (d), (e}} O B= {{a.), fa. c, d). [b, c, d, e}}
Expert Solution
Step 1

(2)

Given a set, X=a, b, c. d, e and τ=, a, c, d, b, c, d, e, a, c, d, X.

To find the sub-base of X, τ.

A set S is said to be a sub-base of a topology, τ, if finite intersections of elements of S forms a basis for τ.

(a) B = , X

Then, the corresponding basis is, 

B'=, X.

By considering the unions of every elements of B', then X and  is only formed.

Therefore, B' does not forms the basis.

Therefore, B is not a sub-base.

Hence, (a) is not true.

(b) B=a, b, c, d, e

Then, the corresponding basis is, 

B'=, a, b, c, d, e

Every element of τ is formed by the union elements of B'. 

Therefore, B' is a basis.

Therefore, B is a sub-base.

(c) B=a, a, c, d, b, c, d, e

Then, the corresponding basis is, 

B=, a, c, d, a, c, d, b, c, d, e

Every element of τ is formed by the union elements of B'. 

Therefore, B' is a basis.

Therefore, B is a sub-base.

Therefore, (b) and (c) are sub-bases.

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