2. Let X = (a, b, c, d, e} and t = {(O, {a, c, d), (b, c, d, e), (a), (C, d), X) then subbase of (X, T) is OB - (0, X) OB = {{a.). (b), (c). (d), (e}} OB= {{a.), (a. c, d), (b, c, d. e})
Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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![7. Let X = {a, b, c, d}, select any two most suitable option *
B={{1,2), (2, 4}} can not be a base for any topology
O One can not find sub base from basis
(0, X) be trivial basis
UB {{1), (2), (3). (4)) be subspace for discrete topology on X
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68f52e0c-1209-4c90-b3f9-cb3983b012e6%2F44fb099f-231f-4420-8b89-8fef93a701b9%2F31rdlt_processed.jpeg&w=3840&q=75)
![2. Let X = {a, b, C, d, e} and t = {(0, {a, c, d), {b, c, d, e), (a), (C, d), X} then subbase of (X, T) is
O B = (0, X)
O B = {{a.). (b), {c), (d), (e}}
O B= {{a.), fa. c, d). [b, c, d, e}}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68f52e0c-1209-4c90-b3f9-cb3983b012e6%2F44fb099f-231f-4420-8b89-8fef93a701b9%2Fywxg4f4_processed.jpeg&w=3840&q=75)
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(2)
Given a set, and .
To find the sub-base of .
A set S is said to be a sub-base of a topology, , if finite intersections of elements of S forms a basis for .
(a) B =
Then, the corresponding basis is,
.
By considering the unions of every elements of B', then X and is only formed.
Therefore, B' does not forms the basis.
Therefore, B is not a sub-base.
Hence, (a) is not true.
(b)
Then, the corresponding basis is,
Every element of is formed by the union elements of B'.
Therefore, B' is a basis.
Therefore, B is a sub-base.
(c)
Then, the corresponding basis is,
Every element of is formed by the union elements of B'.
Therefore, B' is a basis.
Therefore, B is a sub-base.
Therefore, (b) and (c) are sub-bases.
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