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2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value d. df= n-1 X-P t=s √n e. Critical Value: 2.064 f. Normal Curve: Step 5. Conclusion

2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value d. df= n-1 X-P t=s √n e. Critical Value: 2.064 f. Normal Curve: Step 5. Conclusion

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value (C d. df= n-1 t=² √n Critical Value: 2.064 Step 5. Conclusion e. f. Normal Curve:
Transcribed Image Text:2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value (C d. df= n-1 t=² √n Critical Value: 2.064 Step 5. Conclusion e. f. Normal Curve:
2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. STEP 1. The null and alternative hypothesis Ho: μ = 35 Ha: μ # 35 STEP 2. level of significance = x= 0.05 STEP 3. Compare for test statistic Test statistic formula χ-μ Z= O √n = (32 - 35 )/(10/V25) = -1.50 The test statistic is t = -1.50
Transcribed Image Text:2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. STEP 1. The null and alternative hypothesis Ho: μ = 35 Ha: μ # 35 STEP 2. level of significance = x= 0.05 STEP 3. Compare for test statistic Test statistic formula χ-μ Z= O √n = (32 - 35 )/(10/V25) = -1.50 The test statistic is t = -1.50
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