2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value d. df= n-1 X-P t=s √n e. Critical Value: 2.064 f. Normal Curve: Step 5. Conclusion
2. It is claimed that the average age of working students in a certain university is 35 years. A researcher selected a random sample of 25 working students. The sample mean of their ages resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of the working students is different from 35 years? Use 0.05 level of significance and assume normality in the population. Step1. Null & Alternative hypothesis ( Step 2. Level of Significance: 0.05 Step 3. Compute for the test statistic Step 4. Determine the Critical Value d. df= n-1 X-P t=s √n e. Critical Value: 2.064 f. Normal Curve: Step 5. Conclusion
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please answer the other subparts
![2. It is claimed that the average age of working students in a certain
university is 35 years. A researcher selected a random sample of 25
working students. The sample mean of their ages resulted to 32 years
with a standard deviation of 10 years. Does this mean that the average
age of the working students is different from 35 years? Use 0.05 level of
significance and assume normality in the population.
Step1. Null & Alternative hypothesis (
Step 2. Level of Significance: 0.05
Step 3. Compute for the test statistic
Step 4. Determine the Critical
Value (C
d. df= n-1
t=²
√n
Critical Value: 2.064
Step 5. Conclusion
e.
f. Normal Curve:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f9ca16d-6376-477b-9ec5-b2e0296e60a9%2F40ba647d-e370-4c0a-a0bc-a76dfe586a0c%2F64ezv3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. It is claimed that the average age of working students in a certain
university is 35 years. A researcher selected a random sample of 25
working students. The sample mean of their ages resulted to 32 years
with a standard deviation of 10 years. Does this mean that the average
age of the working students is different from 35 years? Use 0.05 level of
significance and assume normality in the population.
Step1. Null & Alternative hypothesis (
Step 2. Level of Significance: 0.05
Step 3. Compute for the test statistic
Step 4. Determine the Critical
Value (C
d. df= n-1
t=²
√n
Critical Value: 2.064
Step 5. Conclusion
e.
f. Normal Curve:
![2. It is claimed that the average age of working students in a certain university is 35 years. A
researcher selected a random sample of 25 working students. The sample mean of their ages
resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of
the working students is different from 35 years? Use 0.05 level of significance and assume
normality in the population.
STEP 1. The null and alternative hypothesis
Ho: μ = 35
Ha: μ # 35
STEP 2. level of significance = x= 0.05
STEP 3. Compare for test statistic
Test statistic formula
χ-μ
Z=
O
√n
= (32 - 35 )/(10/V25)
= -1.50
The test statistic is t = -1.50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f9ca16d-6376-477b-9ec5-b2e0296e60a9%2F40ba647d-e370-4c0a-a0bc-a76dfe586a0c%2F4akuklv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. It is claimed that the average age of working students in a certain university is 35 years. A
researcher selected a random sample of 25 working students. The sample mean of their ages
resulted to 32 years with a standard deviation of 10 years. Does this mean that the average age of
the working students is different from 35 years? Use 0.05 level of significance and assume
normality in the population.
STEP 1. The null and alternative hypothesis
Ho: μ = 35
Ha: μ # 35
STEP 2. level of significance = x= 0.05
STEP 3. Compare for test statistic
Test statistic formula
χ-μ
Z=
O
√n
= (32 - 35 )/(10/V25)
= -1.50
The test statistic is t = -1.50
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