2. In (y(x) + x) = y(x) 1 y (x) + X y! x+y 2 y' "' [ + y -!]. x ty A а y" y' = y" = [y' + 1] = y ₁₁ -x-y x+y x+y = 1-x-y - (lty¹) (x+ty-1)² - 2 yı x+y 1 x+y (x+y-1) (0)-1. [1+y!] (x+y-1)² 1-h+x (Aus.) (Aus)
2. In (y(x) + x) = y(x) 1 y (x) + X y! x+y 2 y' "' [ + y -!]. x ty A а y" y' = y" = [y' + 1] = y ₁₁ -x-y x+y x+y = 1-x-y - (lty¹) (x+ty-1)² - 2 yı x+y 1 x+y (x+y-1) (0)-1. [1+y!] (x+y-1)² 1-h+x (Aus.) (Aus)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can you please solve this question again simply espically the highlited part on the image
![2.
km (y(x) + x) = y(x)
}
1
y (x) + X
y!
x+y
"' [ + y -!].
x ty
A
y':
[y₁ + 1] = y²₁
y₁ [ 1 - x=y=]
-
х+у
y "=
y"
-
"T
x+y
1
=
1-x-y
- (i+y¹)
-
(x+y-1) ²
yı
x+y
x+y
(x+y-1) ()-1. [1+y!]
(x+y-1)²
Xty-1
(Aus.)
(Aus)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F36412e8c-1315-4767-bae1-2fcc926384e1%2F1cc8d128-c835-4bef-8eed-55077e380310%2F0igwbj6_processed.png&w=3840&q=75)
Transcribed Image Text:2.
km (y(x) + x) = y(x)
}
1
y (x) + X
y!
x+y
"' [ + y -!].
x ty
A
y':
[y₁ + 1] = y²₁
y₁ [ 1 - x=y=]
-
х+у
y "=
y"
-
"T
x+y
1
=
1-x-y
- (i+y¹)
-
(x+y-1) ²
yı
x+y
x+y
(x+y-1) ()-1. [1+y!]
(x+y-1)²
Xty-1
(Aus.)
(Aus)
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