2. In this problem we will work with a rotation matrix. Rotation matrices are commonly used for computations in fields such as geometry, physics, and computer graphics. In 3D space, we can rotate an object at position x = (x, y, z) using a rotation matrix. The position x is a column vector representing the x, y, and z coordinates. To rotate the vector counterclockwise by angle about the z-axis, you can multiply x by For b = [10 0 cos 0 sin 0 R(0)x, b is the rotated vector x. R(0) = - 0 sin 8 cost
2. In this problem we will work with a rotation matrix. Rotation matrices are commonly used for computations in fields such as geometry, physics, and computer graphics. In 3D space, we can rotate an object at position x = (x, y, z) using a rotation matrix. The position x is a column vector representing the x, y, and z coordinates. To rotate the vector counterclockwise by angle about the z-axis, you can multiply x by For b = [10 0 cos 0 sin 0 R(0)x, b is the rotated vector x. R(0) = - 0 sin 8 cost
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Matlab program

Transcribed Image Text:2. In this problem we will work with a rotation matrix. Rotation matrices are commonly
used for computations in fields such as geometry, physics, and computer graphics. In
3D space, we can rotate an object at position x = (x, y, z) using a rotation matrix.
The position x is a column vector representing the x, y, and z coordinates. To rotate
the vector counterclockwise by angle about the z-axis, you can multiply x by
0
[1 0
R(0) = 0 cos
0 sin 0
For b= R(0)x, b is the rotated vector x.
1
0
- sin
cost
(a) Write an in-line function that takes in an angle
Using this, calculate R(7/4) and save this as A4.
and returns the matrix R(0).
(b) Rotate the vector x = (-2.3, e, π) about the r-axis using the angle /3. Save the
resulting 3 x 1 vector as A5.
(c) Suppose we have already obtained the 3x1 vector b = (1.2, 3.1,-) from rotating
z around the z-axis by an angle of 7/5. Find z from solving the equation b =
R(0) using standard methods (backslash in MATLAB or solve in Python). Save
the resulting vector as A6.
(d) Find the inverse of the matrix R(7/2) using built-in methods (inv in MATLAB
or scipy. linalg.inv in Python). Save you answer as A7.
=
(e) This is an application where inverse matrices are used quite often, but it is still
a bad idea to actually use the inverse command. But can we figure out an
easier way to do it? The inverse of a rotation is just another rotation. That
is, R(0)- R(), where is a different angle. Find the angle such that
R(3/4)¹ = R(o). Save this answer in a variable named A8. (This does not
require any code, just some geometric reasoning. If you rotate a vector by an
angle 0, what would you have to do to rotate the vector back to where it started?
The answer is not unique, because adding any multiple of 27 to an angle gives
the same rotation matrix. Your answer should be between - and 7.)
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