2. In the year 2005, the average cost of a car could be modeled by the equation C= -15x2 + 20x - 3 where x is the number of years since 2005. By the ye 2010 the average cost had changed, and the equation could be modeled by C= -10x2 + 30x- 2. Find the difference in average cost equation for cars DASHBOARD between 2005 and 2010. COURSES 3. In the following graph of F(x) = -(2/3)(x-3)2 +2 is the preimage of a transformation of G(x)which is the image. What is the mapping stakement for the function G(x)? CALENDAR NBOX G HELP 4. The function P(x) = 3x2 + 4x + 5,is dilated by the function I(x) = P(2x). Write the new function I(x). 5. If f(x) = 3x - 5 and g(x) = 7x + 2. what is (f * g)(x)? O Chat 6. Find the inverse of the function f(x)= 2x - 4 and show explain each step used to find the inverse. 7. Make a box and whisker plot of the following data. Show your work as to how you calculated the different key points on the box-and-whisker plot. 21, 25, 30, 27, 22, 23, 23, 24, 26, 28, 25, 22, 23 8:51 P P Type here to search 98% 9/3/20

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A: Midline is calculated asymax-ymin2 Ymax = -1 Ymin = -3

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A: The given equation is y=-2cosπ3x.

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A: Given function  f(x)=xx2+8 To draw the graph, lets find its properties.

Q: Identify the Points 5 N 4 3. M 2. D -5 -4 -3 -2 4 -1 -2 -3 H -4 -5 1.

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Q: Give the equation for each graph. 5+ 4 3 2 -5 -4 -3 -2 -1 7 1 2 3 4 5

A: The equation for the first  graph  x = -4

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A: Given  P(|X|>70)=0.0099

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A: Topic:- equation of straight line      As we know that equation of line is given by  y= mX +c

Q: Exercise. 1. Graph 3x – 4y = 12.

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Q: #24 what is the correct graph ?

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Q: 3 -3. 3.

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Q: illi. Graph A Graph B Graph C

A: We will tell you about shape of the graph.

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Q: (a) Find the connected components of each graph. (i) G = (V, E). V = {a, b, c, d, e}. E = Ø (ii) G =…

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Q: The following graph shows the point 5m 2, 4

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