Please do not solve the question.My question is why is the angle for Vb -71.57 degree? Shouldn't it be (180+18.43) = 198.43 degree since it is measured from the positive x-axis? A2. In the position shown, bar AB has a constant angularvelocity of 3 rad/s counterclockwise.100 mmВ(a) Determine the angular velocity of bars BD and DE.(b) Determine the angular acceleration of bars BD and DE.200 mm(BJ 15.51 on page 723)Solution:E(a) Set up E-xy. The geometry is given as225 mm75mm'BD = = 225 (mm)= 200 (mm), ľDEА)= 18.43°-1B = tan¬1B= 300 sec(18. 43°)= 316.23 (mm),I BAyВАUsing ö, = 3 k (ccw)(rad/s) and right-hand rule gives@, x řBA = 3(316.23)Z-71.57° = 948.7Z–71.57°.VB2ВEDO

Given : To conclude: The angle which v→B with positive x axis

Answered: 2. In the position shown, bar AB has a…

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2. In the position shown, bar AB has a constant angular velocity of 3 rad/s counterclockwise. (a) Determine the angular velocity of bars BD and DE. (b) Determine the angular acceleration of bars BD and DE. (BJ 15.51 on page 723)