2. In the figure shown AB = 103.20m with A at station 10 + 158.93. The angle VAC is 15'21' and angle VBC is 18°31', where Cis the point to which a simple curve is to be constructed tangent to the line AB. a) Determine the radius of the curve b) Determine the stationing of point C. c) Determine the stationing of P.T. 10+158.93 A 521'C 18'31B P.C. 740o isso

2. In the figure shown AB = 103.20m with A at station 10 + 158.93. The angle VAC is 15'21' and angle VBC is 18°31', where Cis the point to which a simple curve is to be constructed tangent to the line AB. a) Determine the radius of the curve b) Determine the stationing of point C. c) Determine the stationing of P.T. 10+158.93 A 521'C 18'31B P.C. 740o isso

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q#02: Two tangents intersect at chainage 4100 m. Ø 35 35 35". Carry out all the data necessary for setting out the curve, with R = 1000 m and Peg interval being 15 m by: 1) By deflection angle 2) By offsets from chords produced 3) By offset from tangent (Both cases)
2. A compound curve has the following data: I1 = 28°, l2 = 31°, Di = 3º, D2 = 4°; Find the stationing of P.C.C. if P.I. is at station (30 + 120.50). Use arc basis. %3| %3D
The long chord from the P.C to the P.T of a compound curve is 293.77 meters long and the angles its makes with the longer and shorter tangents are 13.94⁰ and 20.32° respectively. If the common tangent is parallel to the long chord, find the stationing of P.T. if the stationing of P.C. is 10 + 233.55. WRITE YOUR ANSWERS in meters. (For example, the stationing is 10+ 252.3 --> write this as 10252.3)
Problem 122 The first-quadrant point on the curve y x = 18 that is closest to the point (2, 0) is а. (2,3) с. (3, уб) b. (6, v3) d. (1,3/2)
A COMPOUND CURVE is composed of three simple curves (CURVE1, CURVE2 & CURVE3).Compute the stationing of PT if the stationing of PC is 6 + 623.56.CURVE1 Radius = 1,157.40 metersCURVE1 Long Chord = 470.80 metersCURVE2 Radius = 550 metersCURVE2 Long Chord = 185.50 metersCURVE3 Radius = 467.87 metersCURVE3 Long Chord = 153.75 meters
Question 1 A highway survey PI falls in a pond, so a cut off line AB = 275.21 ft is run between the tangents. In the triangle formed by points A, B, and PI, the angle at A = 16°28' and at B = 22°16'. The station of A is 54 + 92.30. Calculate and tabulate curve notes to run, by deflection angles and incremental chords, a 4°30' (arc definition) circular curve at full-station increments to connect the tangents.
SITUATION 4: The distance between two intermediate points A and B on a simple curve is 60 m. Their deflection angles are respectively 4° and 10° measured from tangent through PC. 10. Compute the radius of the simple curve. a. 264.90 m c. 246.16 m d. 224.92 m b. 229.47 m 11. Compute the arc length from PC to A. c. 33.74 m а. 34.37 m b. 37.43 m d. 37.34 m 12. Compute the chord length from PC to B. a. 84.59 m b. 89.54 m c. 85.49 m d. 89.45 m
13. The perpendicular offset distance from point A on a simple curve to Q on the tangent line is 64 m. If the distance from the P.C to Q on the tangent is 260 m. Compute the radius of the simple curve. a. 325.60 m b. 560.13 m c. 170.83 m d. 280.065 m
Show complete soln. and illustration.
SITUATION 12: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of simple curve is 4° and PC is at station 20 + 130. 33. Compute the length of the long chord. a. 242.14 m c. 386.12 m d. 284.51 m b. 184.52 m 34. Compute the distance from point D on the simple curve to point of intersection of tangents that makes an angle of 54° with the tangent passing through the PC. а. 30.2 m b. 26.8 m С. 23.4 m d. 31.5 m 35. Compute the stationing of point D. a. 20 + 639.3 b. 20 + 739.3 c. 20 + 439.3 d. 20 + 249.3
TOPIC: Surveying (Horizontal Curves)
plss help