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2.  In paragraph format, address all these items for the results section for EVERY hypotheses:     A.   Type of Data (scale of measurement)      B.  Type of test (name and define the statistical analysis)     C. Statistical Assumptions (define and evaluate)      D.  Define the statistical hypotheses (null and alternative)      E.  State the decision, insert statistics here (use standard phrasing)            a.  (Reject)   “There is sufficient evidence to reject the null hypothesis, state the null,                    include statistics at the end, like r = .23, p < .05."                 OR              b. (Fail to reject)  “There is insufficient evidence to reject the null hypothesis, …”             F. Include a brief interpretation of those findings (use simple language and avoid statistical jargon).

2.  In paragraph format, address all these items for the results section for EVERY hypotheses:     A.   Type of Data (scale of measurement)      B.  Type of test (name and define the statistical analysis)     C. Statistical Assumptions (define and evaluate)      D.  Define the statistical hypotheses (null and alternative)      E.  State the decision, insert statistics here (use standard phrasing)            a.  (Reject)   “There is sufficient evidence to reject the null hypothesis, state the null,                    include statistics at the end, like r = .23, p < .05."                 OR              b. (Fail to reject)  “There is insufficient evidence to reject the null hypothesis, …”             F. Include a brief interpretation of those findings (use simple language and avoid statistical jargon).

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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2.  In paragraph format, address all these items for the results section for EVERY hypotheses:

    A.   Type of Data (scale of measurement)

     B.  Type of test (name and define the statistical analysis)

    C. Statistical Assumptions (define and evaluate)

     D.  Define the statistical hypotheses (null and alternative)

     E.  State the decision, insert statistics here (use standard phrasing)

           a.  (Reject)   “There is sufficient evidence to reject the null hypothesis, state the null,
                   include statistics at the end, like r = .23, p < .05."
                OR

             b. (Fail to reject)  “There is insufficient evidence to reject the null hypothesis, …”      

      F. Include a brief interpretation of those findings (use simple language and avoid statistical jargon).

 

 

AMS STUDY HYPOTHESIS #2 Crosstabs High Amotivation vs Low Amotivation * GPA High (3.0-4.0 vs Low (2.9 and below) Crosstabulation GPA High (3.0-4.0 vs Low (2.9 and below) low GPA High GPA High Low Amotivation Count 67 141 208 Amotivation vs (Motivated) Low Amotivation High Amotivation Expected Count 80.2 127.8 208.0 Count 41 31 72 (Unmotivated) Expected Count 27.8 44.2 72.0 Total Count 108 172 280 Expected Count 108.0 172.0 280.0 Chi-Square Tests Asymptotic Significance Exact Sig. Exact Sig. Value df (2-sided) (2-sided) (1-sided) Pearson Chi-Square 13.809 .000 1 Continuity Correction 12.785 1 .000 Likelihood Ratio 13.547 1 .000 Fisher's Exact Test .000 .000 Linear-by-Linear Association 13.759 1 .000 N of Valid Cases 280 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 27.77. b. Computed only for a 2x2 table Words: 403 Local backup on !!
Transcribed Image Text:AMS STUDY HYPOTHESIS #2 Crosstabs High Amotivation vs Low Amotivation * GPA High (3.0-4.0 vs Low (2.9 and below) Crosstabulation GPA High (3.0-4.0 vs Low (2.9 and below) low GPA High GPA High Low Amotivation Count 67 141 208 Amotivation vs (Motivated) Low Amotivation High Amotivation Expected Count 80.2 127.8 208.0 Count 41 31 72 (Unmotivated) Expected Count 27.8 44.2 72.0 Total Count 108 172 280 Expected Count 108.0 172.0 280.0 Chi-Square Tests Asymptotic Significance Exact Sig. Exact Sig. Value df (2-sided) (2-sided) (1-sided) Pearson Chi-Square 13.809 .000 1 Continuity Correction 12.785 1 .000 Likelihood Ratio 13.547 1 .000 Fisher's Exact Test .000 .000 Linear-by-Linear Association 13.759 1 .000 N of Valid Cases 280 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 27.77. b. Computed only for a 2x2 table Words: 403 Local backup on !!
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