2. In each case, write the function f(z) in the form f(z) = u(x, y) + iv(x, y): z² (a) f(z)=z³+z+1; (b) f(z) = == (z =0). Suggestion: In part (b), start by multiplying the numerator and denominator by z. Ans. (a) f(z) = (x³ - 3xy² + x + 1) +i (3x²y - y³ + y); x3 - 3ху2 y³ - 3x²y x² + y² x² + y² (b) f(z) = +i Z
2. In each case, write the function f(z) in the form f(z) = u(x, y) + iv(x, y): z² (a) f(z)=z³+z+1; (b) f(z) = == (z =0). Suggestion: In part (b), start by multiplying the numerator and denominator by z. Ans. (a) f(z) = (x³ - 3xy² + x + 1) +i (3x²y - y³ + y); x3 - 3ху2 y³ - 3x²y x² + y² x² + y² (b) f(z) = +i Z
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:2. In each case, write the function f(z) in the form f(z) = u(x, y) + iv(x, y):
7.²
(a) f(z) = z³ +z+1; (b) f(z) =
(z = 0).
Z
Suggestion: In part (b), start by multiplying the numerator and denominator by z.
Ans. (a) f(z) = (x³ - 3xy² + x + 1) +i (3x²y - y³ + y);
x³ - 3xy²y³ - 3x²y
3
+i
x² + y²
x² + y²
(b) f(z) =
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